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How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
How many grams of C6H12O6 are need to produce 8.57 millimoles?
Mol wt of C6H12O6 = 6*12 + 1*12 + 16*6 = 72+12+96 = 180 This implies that 180 grams of the compound is equivalent to 1 mole 1 mole = 180 grams => 1 millimole = 180 milligrams => 8.57 millimoles = 180*8.57= 1542.6 milligrams = 1.5426 grams
How many moles of sugar (C6H12O6) are in one can of soda?
One can of soda typically contains around 40 grams of sugar. To calculate the number of moles of sugar, divide the mass of sugar by its molar mass (180.16 g/mol for C6H12O6). This would give roughly 0.22 moles of sugar in one can of soda.
How many grams are contained in 5.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.
How many moles are contained in 15.01 grams of argon?
To find the number of moles in 15.01 grams of argon, you need to divide the given mass by the molar mass of argon. The molar mass of argon is approximately 39.95 g/mol. So, the number of moles of argon in 15.01 grams would be 15.01 g / 39.95 g/mol = 0.376 moles.
How many grams of carbon dioxide would be produced if 45 g of C6H12O6 competely reacted with oxygen?
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
How many grams is contained in 0.27 moles of calcium?
0,27 moles of calcium contain 10,82 g calcium.
How many grams of carbon dioxide would be produced if 45 g of C6H12O6 completely reacted with oxygen?
The balanced chemical equation for the combustion of glucose (C6H12O6) is: C6H12O6 + 6O2 -> 6CO2 + 6H2O. From the equation, we can see that 1 mol of C6H12O6 produces 6 mol of CO2. First, calculate the number of moles of C6H12O6 in 45 g. Then use the mole ratio to find the moles of CO2 produced, and finally convert that to grams.
How many grams are equal to 450 milligrams?
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
How many grams of C6H12O6 are need to produce 8.57 millimoles?
Mol wt of C6H12O6 = 6*12 + 1*12 + 16*6 = 72+12+96 = 180 This implies that 180 grams of the compound is equivalent to 1 mole 1 mole = 180 grams => 1 millimole = 180 milligrams => 8.57 millimoles = 180*8.57= 1542.6 milligrams = 1.5426 grams
How many moles of sugar (C6H12O6) are in one can of soda?
One can of soda typically contains around 40 grams of sugar. To calculate the number of moles of sugar, divide the mass of sugar by its molar mass (180.16 g/mol for C6H12O6). This would give roughly 0.22 moles of sugar in one can of soda.
The body can absorb up to 120 grams of carbohydrate per hour from the small intestine. If we assume this is all in the form of glucose how many moles of glucose have been absorbed?
0.67 moles of C6H12O6
What is 16 grams of oxygen how many moles?
16 grams of oxygen how many moles is 0,5 moles.
How many molecules are in 720 grams of C6H12O6?
To determine the number of molecules in 720 grams of C6H12O6 (glucose), you first need to calculate the number of moles present. The molar mass of glucose is 180.16 g/mol. Dividing 720 grams by the molar mass gives you 4 moles of C6H12O6. One mole of any substance contains Avogadro's number of molecules, which is approximately 6.022 x 10^23. Therefore, 4 moles of C6H12O6 would contain about 2.409 x 10^24 molecules.
How many grams are contained in 5.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.
When 9.00 g c6h1206 burns with excess oxygen how many grams of co2 will be made?
C6H12O6 + 6O2 ==> 6CO2 + 6H2O (balanced equation)9.00 g x 1 mole/180 g = 0.05 moles C6H12O60.05 moles C6H12O6 x 6 moles CO2/1 mole C6H12O6 x 44 g CO2/mole CO2 = 13.2 g CO2 formed
