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How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
How many grams of C6H12O6 are need to produce 8.57 millimoles?
Mol wt of C6H12O6 = 6*12 + 1*12 + 16*6 = 72+12+96 = 180 This implies that 180 grams of the compound is equivalent to 1 mole 1 mole = 180 grams => 1 millimole = 180 milligrams => 8.57 millimoles = 180*8.57= 1542.6 milligrams = 1.5426 grams
How many moles of sugar (C6H12O6) are in one can of soda?
One can of soda typically contains around 40 grams of sugar. To calculate the number of moles of sugar, divide the mass of sugar by its molar mass (180.16 g/mol for C6H12O6). This would give roughly 0.22 moles of sugar in one can of soda.
How many grams are contained in 5.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.
A sample of C6H12O6 has a mass of 300g How many moles of C atoms H atoms and O atoms are in the sample?
C6H1206 has 6 Carbon atoms, 12 Hydrogen atoms, and 6 Oxygen atoms, otherwise known as Glucose, a plant food made for long-term storage. Sorry if that's not what you're looking for! Added: This is what you are looking for. 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 mole C/1 mole C6H12O6)(6.022 X 10^23/1 mole C)(1 mole C/6.022 X 10^23) = 9.99 moles Carbon atoms in that mass glucose 300 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(12 mole H/1 mole C6H12O6)(6.022 X 10^23/1 mole H)(1 mole H/6.022 X 10^23) = 19.98 moles Hydrogen atoms in that mass glucose Now, you have seen two examples of this procedure, so you do the oxygen number crunching.
How many grams of carbon dioxide would be produced if 45 g of C6H12O6 competely reacted with oxygen?
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
How many grams is contained in 0.27 moles of calcium?
0,27 moles of calcium contain 10,82 g calcium.
How many grams of carbon dioxide would be produced if 45 g of C6H12O6 completely reacted with oxygen?
The balanced chemical equation for the combustion of glucose (C6H12O6) is: C6H12O6 + 6O2 -> 6CO2 + 6H2O. From the equation, we can see that 1 mol of C6H12O6 produces 6 mol of CO2. First, calculate the number of moles of C6H12O6 in 45 g. Then use the mole ratio to find the moles of CO2 produced, and finally convert that to grams.
How many grams are equal to 450 milligrams?
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
How many grams of C6H12O6 are need to produce 8.57 millimoles?
Mol wt of C6H12O6 = 6*12 + 1*12 + 16*6 = 72+12+96 = 180 This implies that 180 grams of the compound is equivalent to 1 mole 1 mole = 180 grams => 1 millimole = 180 milligrams => 8.57 millimoles = 180*8.57= 1542.6 milligrams = 1.5426 grams
How many moles of sugar (C6H12O6) are in one can of soda?
One can of soda typically contains around 40 grams of sugar. To calculate the number of moles of sugar, divide the mass of sugar by its molar mass (180.16 g/mol for C6H12O6). This would give roughly 0.22 moles of sugar in one can of soda.
The body can absorb up to 120 grams of carbohydrate per hour from the small intestine. If we assume this is all in the form of glucose how many moles of glucose have been absorbed?
0.67 moles of C6H12O6
How many molecules are in 720 grams of C6H12O6?
To determine the number of molecules in 720 grams of C6H12O6 (glucose), you first need to calculate the number of moles present. The molar mass of glucose is 180.16 g/mol. Dividing 720 grams by the molar mass gives you 4 moles of C6H12O6. One mole of any substance contains Avogadro's number of molecules, which is approximately 6.022 x 10^23. Therefore, 4 moles of C6H12O6 would contain about 2.409 x 10^24 molecules.
What is 16 grams of oxygen how many moles?
16 grams of oxygen how many moles is 0,5 moles.
When 9.00 g c6h1206 burns with excess oxygen how many grams of co2 will be made?
C6H12O6 + 6O2 ==> 6CO2 + 6H2O (balanced equation)9.00 g x 1 mole/180 g = 0.05 moles C6H12O60.05 moles C6H12O6 x 6 moles CO2/1 mole C6H12O6 x 44 g CO2/mole CO2 = 13.2 g CO2 formed
How many grams are contained in 5.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.
