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What amount of solid Naoh must be added to 750g of an aqueous solution to make 2.5 percent naoh solution by mass?
You would need to add 18.75g of solid NaOH to the 750g of aqueous solution to obtain a 2.5% NaOH solution by mass.
What is the maximum amount of P4 that can be produced from 1.0kg of phosphorite if the phorphorite sample is 75 Ca3PO42 by mass?
2Ca3(PO4)2 + 6SiO2 + 10 C -> 6CaSiO3 + P4 + 10 CO There is 1 kg of solution. 75% of the solution is Ca3(PO4)2. Change 1kg to grams which is 1000g. 75% of 1000 is 750 Therefore there is 750g of the Ca3(PO4)2. Find the mole of Ca3(PO4)2 which is the mass divided by the molar mass. 750g/310.4gmol-1 which equals n =2.4mol ...1/2 is the ratio so mol of P4 is 1.2 mol. to find the mass of P4 you do M * n = 1.2mol * 148.65 therefore the max amount of P4 that can be produced is 150g
How many calories of heat is available when a hot water bottle containing 750g of water at 65 degrees cools to body temperature?
To calculate the calories of heat available when the water cools to body temperature, you need to consider the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C. By using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change, you can find the answer.
How much heat will it take to raise 750 g of water from 25.0 degrees celsius to 75.0 degrees celsius?
The heat required can be calculated using the formula Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature. So, plugging in the values, Q = 750g * 4.18 J/g°C * (75.0°C - 25.0°C) = 187,650 Joules.
What happens to the temperature when you mix hot and cold water together?
This can be confusing at first but after you do the calculations there is really nothing to it. NOTE: adding temperatures DOES NOT work for this eg if you have 53 degrees C of water and you add 32 degrees C of water, despite how much I wish that it worked like that and so that our energy bills wouldn't cost a thing, the final temperature is NOT 85 degrees C nor vice versa The easiest method of calculating the change of temperature is to know the heat energy of the system. Whereby Q = mcT m = mass of water in this case c = heat capacity of water T = Temperature in Kelvin I believe so take 33 mL of water at 45 degrees C and add that to 750 mL of water at 87 degree C Calculate the respective energies and add them together: we have c = 4.1855 [J/(g·K)] (15 °C, 101.325 kPa) m1 = 33g T1 = 45 + 273 = 318 degrees K Q1 = 43.922 Joules m2 = 750g T2 = 87 + 273 = 360 degrees K Q2 = 1130.085 Joules Now Qfinal = mfinal * c * T final so Qfinal = Q1 + Q2 = 1174.007 Joules mfinal = 33 + 750 = 783g therefore the final temp of the system must be (given that I've got the correct values so far :P ) : Tfinal = Qfinal /mfinal *c Tfinal = 358 degree K or 85.23 degrees C, which makes sense if you think about it, as most of the water was hotter, and you only added a small amount of cold, meaning that the temp. shouldn't, if you think about it, drop too substantially. Hope this helps. Cheers.
What is 0.75kg change to grams?
750g
What is 750g of 1kg?
There are 1000 grams in one kilogram. Therefore, 7500 grams is equal to 7500/1000 = 7.5 kilograms.
What is 750G equal to in pounds?
1.653 pounds.
What is half of 1.5 kilogram?
It is 1500 grams.
How many lbs is 750 g?
750g is 1.65347 pounds.
How much is 750g of potatoes?
The cost of 750g of potatoes in the UK is (February 2011) about £1.72 in Sainsburys but I believe they're cheaper in ASDA. The imperial equivalent to 750 g (grams) is 1.65 lb (pounds).
What is the cost of 750g at 48p per half kg?
To calculate the cost of 750 grams at 48 pence per half kilogram (500 grams), first determine the cost per gram. Since 48 pence is for 500 grams, the cost per gram is 48p / 500g = 0.096p per gram. For 750 grams, the cost would be 750g × 0.096p/g = 72p. Therefore, the cost of 750 grams is 72 pence.
What fraction of 1kg is 750g?
1000 grams = 1 kilogram 750 grams = 750/1000 = 3/4 kilogram (as a fraction in its simplest form).
How many grams of sodium fluoride are needed to prepare a 0.400m NaF solution that contains 750g of water?
To prepare a 0.400m NaF solution, you need to dissolve 0.400 moles of NaF per liter of solution. With 750g of water, you have about 0.416 L of water. To calculate the grams of NaF needed, multiply the molarity by the volume of solution in liters, then multiply by the molar mass of NaF (sodium fluoride: 41.99 g/mol). So, you would need about 6.991 grams of NaF.
How many grams in three quarters of a kilogram?
1 kilogram = 1000g 1 quarter = 250g so, 3 quarters = 750g
How many teaspoons in 750g?
That is approximately 1 pound , 10.45 ounces
What is 750g ratio 1kg?
Oh, dude, 750g is like 0.75kg. So, the ratio of 750g to 1kg is 0.75:1. It's like saying you have 75% of a kilogram, but who's really counting, right?
