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How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
How many moles are contained in 15.8 grams of C6H12O6?
To find the number of moles in 15.8 grams of C6H12O6, first calculate the molar mass of C6H12O6 which is 180 g/mol (126 + 112 + 16*6). Then divide the given mass by the molar mass to get the number of moles. In this case, 15.8g / 180 g/mol = 0.088 moles.
How many millimoles of HNO3 are present at the start of a titration?
The number of millimoles of HNO3 present at the start of a titration will depend on the initial concentration and volume of the HNO3 solution. To calculate millimoles, you can multiply the concentration of HNO3 in moles per liter by the volume of the solution in liters.
How many grams of 2na plus cL2 would be required to produce 4 grams of table salt?
To produce 4 grams of table salt (NaCl), you would need 2 moles of Na and 1 mole of Cl2. This corresponds to 46 grams of Na and 71 grams of Cl2. This would total 117 grams of reactants (2Na + Cl2) to produce 4 grams of NaCl.
How many moles of H2O are needed in order to produce 1 mole of glucose?
You need to dissolve 180 grams of glucose in water and make it up to 1000ml. this produces 1 M Glucose solution.
How many grams of carbon dioxide would be produced if 45 g of C6H12O6 competely reacted with oxygen?
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
How many grams are equal to 450 milligrams?
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
How many milimoles are in 35 grams of glucose?
The molar mass of glucose is 180,16 grams.180,16 g------------1 mol35 g------------------xX = 0,194 moles or 194 millimoles
How many moles are contained in 15.8 grams of C6H12O6?
To find the number of moles in 15.8 grams of C6H12O6, first calculate the molar mass of C6H12O6 which is 180 g/mol (126 + 112 + 16*6). Then divide the given mass by the molar mass to get the number of moles. In this case, 15.8g / 180 g/mol = 0.088 moles.
How many molecules of CO2 are needed to produce 1 molecule of glucose (C6H12O6)?
3.
How many grams of carbon dioxide would be produced if 45 g of C6H12O6 completely reacted with oxygen?
The balanced chemical equation for the combustion of glucose (C6H12O6) is: C6H12O6 + 6O2 -> 6CO2 + 6H2O. From the equation, we can see that 1 mol of C6H12O6 produces 6 mol of CO2. First, calculate the number of moles of C6H12O6 in 45 g. Then use the mole ratio to find the moles of CO2 produced, and finally convert that to grams.
How many grams of ammonia NH3 will produce 300 grams of N2?
394.794 grams
How many grams of H2SO4 will 200 grams of SO3 and 100 grams of H2O produce?
About 245 grams.
How many grams of carbon dioxide would be produced if 45 grams of glucose completely react with oxygen?
The chemical equation for the combustion of glucose is C6H12O6 + 6O2 -> 6CO2 + 6H2O. From this, we can see that 1 mole of glucose produces 6 moles of CO2. Therefore, 45 grams of glucose (which is approximately 0.25 moles) would produce 6 times that amount of CO2, which is about 90 grams.
How many micromoles is 0.59 millimoles?
There are 1000 micromoles in a millimole. Therefore you have to multiply by 1000. 0.59mmol is 0.59x1000 or 590 micromoles.
How many grams of chloral are needed to produce 10.5 g DDT?
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
