Mol wt of C6H12O6 = 6*12 + 1*12 + 16*6 = 72+12+96 = 180
This implies that 180 grams of the compound is equivalent to 1 mole
1 mole = 180 grams
=> 1 millimole = 180 milligrams
=> 8.57 millimoles = 180*8.57= 1542.6 milligrams = 1.5426 grams
15.8 grams of C6H12O6 is equivalent to 0.087 moles.
14.7 g
All the simple sugars having the formula C6H12O6 are completely covalently bonded and thus produce no ions when they dissolve.
63.3 g
2
15.8 grams of C6H12O6 is equivalent to 0.087 moles.
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
14.7 g
The molar mass of glucose is 180,16 grams.180,16 g------------1 mol35 g------------------xX = 0,194 moles or 194 millimoles
All the simple sugars having the formula C6H12O6 are completely covalently bonded and thus produce no ions when they dissolve.
3.
888
394.794 grams
About 245 grams.
i think that you have to add 100 gramd to produce the amount of 900 grams
431.5 grams A+LS =^.^=