1.5 moles of N2O5
Each molecule of NO3 contains one atom of nitrogen, so 3 moles of the compound will contain 3 moles of N atoms. However, N2O5 molecules each contain two nitrogen atoms, so each mole of N2O5 has two moles of nitrogen. So, in order to have three moles of N atoms, you need only 3/2 = 1.5 moles of N2O5.
The formula for NO2 contains three atoms, one of nitrogen and two of oxygen. If the question was intended to be about the number of atoms in a sample of the compound, that depends on the size of the sample.
3.01 X 10^24 atoms NO2 (1mol N)2/6.022 X 10^23)
= 4.998 moles ( call it 5.00 )
there is one nitrogen and 2 oxygen atoms
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moles = x molecules x 1 mole/6.02x10^23 molecules, or put another way
moles = x/6.02x10^23
Nitrogen monoxide(NO) has one mole of nitrogen and one mole of oxygen.
One mole is 6.022 x 1023 atoms. Therefore, one mole of NO has 12.044 x 1023 atoms
3.... one N two O.
The answer is 7,72 moles.
6.022 x 1023 x 2 = 1.2044 x 1024
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
The answer is 1,21 moles.
1 mole of O2 contains 6.02 x 1023 molecules. In 2.045 x 1021 molecules, there are ( 2.045 x 1021 / 6.02 x 1023 ) moles = 0.0034 moles.
6.022 x 1023 x 2 = 1.2044 x 1024
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
1 mole of molecules = 6.022 x 1023 molecules 1.25 moles of molecules x 6.022 x 1023 molecules/mol molecules = 7.53 x 1023 molecules
1 mole of H2 has 6.023 x 1023 molecules So, 2 moles will have 12.046 x 1023 molecules
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
The answer is 1,21 moles.
1 mole of O2 contains 6.02 x 1023 molecules. In 2.045 x 1021 molecules, there are ( 2.045 x 1021 / 6.02 x 1023 ) moles = 0.0034 moles.
The answer is 4 moles.
The equivalence is 1992 moles.
2.4 x (6.022x1023) = 1.44528x1024 molecules of butane number of moles (of molecules) x avgadro's constant(6.022x1023) = number of molecules
6,022140857.1023 molecules---------------------------------------------1 mole2.1022 molecules--------------------------------------------------------------x molex = 0,033 moles
1 mole of any substance contains Avogadro's number of particles (molecules). 6.022 x 1023 molecules / mole x 2.16 moles = 1.300752 x 1024 molecules