The equivalence is 1992 moles.
1.305 mol CO
1,4 moles carbon monoxide are produced.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
350 g sample of CO contain 12,49 moles.
To find the mass of carbon monoxide needed, we need to use the stoichiometric ratio between iron and carbon monoxide. From the balanced equation, we can see that 3 moles of carbon monoxide produce 2 moles of iron. First, calculate the molar mass of iron (Fe), which is 55.85 g/mol. Next, use the molar ratio between iron and carbon monoxide (2:3) to find the moles of carbon monoxide required. Finally, convert the moles of carbon monoxide to grams using its molar mass (28.01 g/mol).
Two molecules of Carbon monoxide. I think not two molecules but two moles of carbon monoxide .i,e 2CO.
In order to find number of molecules from moles, you must multiply moles by avagadro's number, which is 6.02*10^23.
1.305 mol CO
2,22 1023 molecules of carbon dioxide is equal to 0,368 moles.
To get moles given representative particles, simply divide by Avogadro's number: 1.80x1024/6.02x1023 = approx. 3 moles I2.
1,4 moles carbon monoxide are produced.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
Multiply by avagadro constant. It is equals to 6.022*1^23
5.01020 molecules carbon ( 1 mole C/6.022 X 10^23 ) = 8.3198 X 10^24 moles carbon
2,55 moles of the compound CO have 71,4 grams.
350 g sample of CO contain 12,49 moles.
To find the mass of carbon monoxide needed, we need to use the stoichiometric ratio between iron and carbon monoxide. From the balanced equation, we can see that 3 moles of carbon monoxide produce 2 moles of iron. First, calculate the molar mass of iron (Fe), which is 55.85 g/mol. Next, use the molar ratio between iron and carbon monoxide (2:3) to find the moles of carbon monoxide required. Finally, convert the moles of carbon monoxide to grams using its molar mass (28.01 g/mol).