There are 3 atoms in a formula unit of FeCl3 1 of iron and 3 of chlorine.
Iron chloride has a molar mass of 162 grams per mole. To find the number of moles, divide the mass of the sample by the molar mass.
FeCl3 = 162.4 g/mole
1.1 grams ÷ 162.4 grams/mol = 0.0068 moles
This molarity is 0,0068 for the anhydrous salt.
3 moles of FeCl2 is equivalent to 380,253 g. And 3 moles contain 18,066 422 571.10e23 formula units.
3 mole Fe3O4 equals 2 mole Fe2O3
The answer is 0,01 moles.
162.2 g/mol
1.1 grams of FeCl 3
To find the grams of NaCl in 11 moles, you need to multiply the number of moles by the molar mass of NaCl (58.44 g/mol). Therefore, 11 moles of NaCl is equal to 11 * 58.44 = 642.84 grams.
65.39 grams titanium (1 mole Ti/47.87 grams)(6.022 X 1023/1 mole Ti) = 8.226 X 1023 atoms of titanium -------------------------------------------
each mole contains 6.022*10(raised to the power 23) so three moles of sodium contain 18.066*10(raised to the power 23) mass of one mole of sodium is 11 grams so mass of three moles of sodium is 33 grams
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
To find the number of moles of THC in 27 nanograms, you first need to convert nanograms to grams (1 ng = 1e-9 g). Then use the molar mass of THC (C21H30O2) to convert grams to moles. Next, you can calculate the number of molecules using Avogadro's number (6.022e23 molecules/mol). The exact calculations would be: (27e-9 g THC) / (314.46 g/mol THC) = 8.59e-11 moles, and (8.59e-11 moles) * (6.022e23 molecules/mol) = 5.17e13 molecules.
To find the grams of NaCl in 11 moles, you need to multiply the number of moles by the molar mass of NaCl (58.44 g/mol). Therefore, 11 moles of NaCl is equal to 11 * 58.44 = 642.84 grams.
11
11 g hydrogen are needed.
65.39 grams titanium (1 mole Ti/47.87 grams)(6.022 X 1023/1 mole Ti) = 8.226 X 1023 atoms of titanium -------------------------------------------
11 grams of silicon Si equals 0,39 moles.
C + O2 = CO2 So the theoretical number of moles are 1 each. number of moles is mass/molecular weight C = 6/12 which is 0.5 O2 = 11/32 which is 0.34375 Oxygen is the limiting reagent. So 0.34375 moles is reacted and this also gives 0.34375 moles CO2 no moles is mass over molecular mass grams is moles x molec mass 0.34375 x 44 = 15.125 grams CO2 formed. learn the technique. this is needed in science
Approximately 0.3915984336 mol ... or simply, 0.39 moltake the number 11 from 11g, and divide it by the molar mass of Si on the periodic table, which is the number with usually a decimal. This is how to get moles from grams for any element.
each mole contains 6.022*10(raised to the power 23) so three moles of sodium contain 18.066*10(raised to the power 23) mass of one mole of sodium is 11 grams so mass of three moles of sodium is 33 grams
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
First, calculate the number of moles of HCl using the molar mass. Then, determine the number of moles of NaOH needed to neutralize the HCl based on the 1:1 stoichiometry of the reaction. Finally, use the molarity of NaOH to find the volume required using the formula Molarity = moles/volume.
4989.52 grams to 11 pounds.
31.1844754 grams