The Atomic Mass of B is 10.8Amount of B = mass of pure sample/molar mass = 31.78/10.8 = 2.94mol
There are 2.94 moles of the element boron in a 31.78g pure sample.
1.00*10-7 moles of boron is how many grams is this
Divide it by Avogadro constant.There are 0.0088 moles
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
Boron has five protons.The element boron has 5 protons.5
15.8 mol B = 9.51 X 1024 atoms.15.8 mol (6.02 X 1023/ 1 mol) = 9.5116 X 1024
1.00*10-7 moles of boron is how many grams is this
24.092X1023
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
Divide it by Avogadro constant.There are 0.0088 moles
Each mole of boron atoms has a mass of 10.811 grams, as indicated by the gram atomic mass or weight of boron. Therefore, 585 moles has a mass of about 6.32 X 103 grams, to the same number of significant digits as 585.
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
This mass is 101,6505 g.The atomic masses of hydrogen and boron are 11 and 1 respectively. The relative molecular mass of the compound is 14. Therefore the mass of 7.35 moles is approximately 102.9 grams.
Boron has five protons.The element boron has 5 protons.5
15.8 mol B = 9.51 X 1024 atoms.15.8 mol (6.02 X 1023/ 1 mol) = 9.5116 X 1024
boron has 2 pairs
Boron has 5 protons.
Boron has 5 protons.