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The Atomic Mass of B is 10.8Amount of B = mass of pure sample/molar mass = 31.78/10.8 = 2.94mol
There are 2.94 moles of the element boron in a 31.78g pure sample.
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How many grams are in one mole of boron?
1.00*10-7 moles of boron is how many grams is this
Calculate the number of moles in 5.34 10 21 atoms of boron?
To calculate the number of moles, first calculate the molar mass of boron (B), which is approximately 10.81 g/mol. Then use the Avogadro's number (6.022 x 10^23) to convert the number of atoms to moles. So, moles = number of atoms / Avogadro's number = 5.34 x 10^21 / 6.022 x 10^23 ≈ 0.089 moles of boron.
How many atoms are in 15.8 moles of boron?
To calculate the number of atoms in 15.8 moles of boron, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mole. Multiply 15.8 moles by Avogadro's number to get approximately 9.5 x 10^24 atoms of boron.
How many moles of B in 20g of borax?
To calculate the number of moles in 20g of borax (Na2B4O7), we first need to find the molar mass of borax. By adding the atomic masses of all the elements in borax, we get a molar mass of approximately 201.22 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting in the values, we find that there are approximately 0.10 moles of borax in 20g. Since there are four boron atoms in one molecule of borax, the number of moles of B (boron) would be 0.10 moles * 4 = 0.40 moles.
How many moles are in 97.2 grams of boron?
To do this, you need to know the atomic weight of the element you're dealing with, found on any periodic table. The atomic weight is the mass in grams of the element in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the atomic weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the atomic weight. That's the thought process behind unit analysis and how you get your "units to cancel".In this case, the answer is about 8.99 moles B.
How many atoms are in 4.0 moles of boron?
There are 4.81 x 10^24 atoms in 4.0 moles of boron. This value is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles of boron.
How many moles of fluorine in 3 moles of borontrifluoride?
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
How many grams are in one mole of boron?
1.00*10-7 moles of boron is how many grams is this
Calculate the number of moles in 5.34 10 21 atoms of boron?
To calculate the number of moles, first calculate the molar mass of boron (B), which is approximately 10.81 g/mol. Then use the Avogadro's number (6.022 x 10^23) to convert the number of atoms to moles. So, moles = number of atoms / Avogadro's number = 5.34 x 10^21 / 6.022 x 10^23 ≈ 0.089 moles of boron.
How many atoms are in 15.8 moles of boron?
To calculate the number of atoms in 15.8 moles of boron, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mole. Multiply 15.8 moles by Avogadro's number to get approximately 9.5 x 10^24 atoms of boron.
How many moles of B in 20g of borax?
To calculate the number of moles in 20g of borax (Na2B4O7), we first need to find the molar mass of borax. By adding the atomic masses of all the elements in borax, we get a molar mass of approximately 201.22 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting in the values, we find that there are approximately 0.10 moles of borax in 20g. Since there are four boron atoms in one molecule of borax, the number of moles of B (boron) would be 0.10 moles * 4 = 0.40 moles.
What is the mass of a boron sample which contains 585 moles of b atoms?
Each mole of boron atoms has a mass of 10.811 grams, as indicated by the gram atomic mass or weight of boron. Therefore, 585 moles has a mass of about 6.32 X 103 grams, to the same number of significant digits as 585.
How many moles are in 97.2 grams of boron?
To do this, you need to know the atomic weight of the element you're dealing with, found on any periodic table. The atomic weight is the mass in grams of the element in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the atomic weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the atomic weight. That's the thought process behind unit analysis and how you get your "units to cancel".In this case, the answer is about 8.99 moles B.
What would you multiply atoms of boron by to get the units grams of boron?
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
What approximate mass would a sample of naturally occurring boron (B) that contains 1 and times 106 atoms of boron have?
The molar mass of boron is approximately 10.81 g/mol. To calculate the mass of 1 x 10^6 boron atoms, you divide 6.022 x 10^23 (Avogadro's number) by 1 x 10^6 to find the number of moles, which equals 0.001673 moles. Multiply this by the molar mass of boron to get approximately 0.0181 grams.
What is the mass of 7.35 moles of boron trihydride?
This mass is 101,6505 g.The atomic masses of hydrogen and boron are 11 and 1 respectively. The relative molecular mass of the compound is 14. Therefore the mass of 7.35 moles is approximately 102.9 grams.
How many electrons are in boron?
there are 5 electrons in boron atoms.
