Given the balanced equation
2C3H8O + 9O2 --> 6CO2 + 8H2O
To find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).
0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2
---------- 2 molecules C3H8O
The reaction between Isopropyl alcohol and oxygen is 2 C3H8O + 9 O2 equals 6 CO2 + 8 H2O. So for every mole of isopropyl alcohol, 4.5 moles of oxygen are consumed. 6.5 grams of C3H8O is .108 moles and 12.3 grams of O2 is .384 moles. This means that O2 is the limiting reactant as it needs .486 moles of O2 to finish.
Formula: C3H7OH
2(c3h8o)+9o2 => 8h2o+6co2
Yes, and the solution is H2O, C3H8O
Propanol (1-propanol) is the chemical name for the molecular formula of C3H8O. The structure of 1-propanol is: H C C I I IH-C-C -C-OH I I I H H H
Carbon dioxide and Water are produced The chemical equation for it is C3H8O + O2 = CO2 + H2O Balance form (if needed) is: 2C3H8O + 9O2 = 6CO2 + 8H2O
Carbon dioxide and Water are produced The chemical equation for it is C3H8O + O2 = CO2 + H2O Balance form (if needed) is: 2C3H8O + 9O2 = 6CO2 + 8H2O
Dipropyl ether
Complete combustion : 2C3H8O + 9O2 --> 6CO2 + 8H2O Incomplete combustion : C3H8O + 3O2 --> 3CO + 4H2O
42.1g/ 59g/mol (grams/molar mass of C3H8O)
The reaction between Isopropyl alcohol and oxygen is 2 C3H8O + 9 O2 equals 6 CO2 + 8 H2O. So for every mole of isopropyl alcohol, 4.5 moles of oxygen are consumed. 6.5 grams of C3H8O is .108 moles and 12.3 grams of O2 is .384 moles. This means that O2 is the limiting reactant as it needs .486 moles of O2 to finish.
C3H8O ==== Count them.
C3H8O ==== Count them.
Formula: C3H7OH
200 molecules C3H8O (1 mole C3H8O/6.022 X 10^23)(3 mole C/1 mole C3H8O)(6.022 X 10^23/1 mole C) = 600 molecules of carbon atoms -------------------------------------------- Of course, you can just look at this set up and see there are 600 molecules. My answer set up is a formal set up. ( 200 * 3 would do it )
2(c3h8o)+9o2 => 8h2o+6co2
The melting point of 1-propanol is -126 oC.