42.1g/ 59g/mol (grams/molar mass of C3H8O)
To determine the amount of water and propene that can be formed, we first need to write out the balanced chemical equation for the reaction of 2-propanol (C3H8O) to form water (H2O) and propene (C3H6): C3H8O -> C3H6 + H2O Next, calculate the molar mass of 2-propanol (60.1 g/mol) and the molar masses of water (18.0 g/mol) and propene (42.1 g/mol). Then, use stoichiometry to convert the mass of 2-propanol to moles, and from there determine the amount of water and propene that can be formed.
To find the grams of H2O and C3H6 formed from 6g of C3H8O, first calculate the molar mass of C3H8O: 44.1 g/mol. Then, using the stoichiometry of the reaction yielding H2O and C3H6 from C3H8O, you can determine the grams produced. The balanced reaction is C3H8O -> H2O + C3H6, and for every 1 mol of C3H8O, you get 1 mol of H2O and 1 mol of C3H6. So, 6g of C3H8O yields 6g of H2O and 6g of C3H6.
The structural formulas for the propyl alcohol isomers are as follows: n-propyl alcohol (1-propanol): CH3CH2CH2OH or C3H8O Isopropyl alcohol (2-propanol): (CH3)2CHOH or C3H8O These structural formulas represent the arrangement of atoms in the molecule of each isomer.
For 2-propanol, there are 9 fundamental vibrations: 3 translational, 3 rotational, and 3 vibrational modes.
200 molecules C3H8O (1 mole C3H8O/6.022 X 10^23)(3 mole C/1 mole C3H8O)(6.022 X 10^23/1 mole C) = 600 molecules of carbon atoms -------------------------------------------- Of course, you can just look at this set up and see there are 600 molecules. My answer set up is a formal set up. ( 200 * 3 would do it )
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
alcohol
To determine the amount of water and propene that can be formed, we first need to write out the balanced chemical equation for the reaction of 2-propanol (C3H8O) to form water (H2O) and propene (C3H6): C3H8O -> C3H6 + H2O Next, calculate the molar mass of 2-propanol (60.1 g/mol) and the molar masses of water (18.0 g/mol) and propene (42.1 g/mol). Then, use stoichiometry to convert the mass of 2-propanol to moles, and from there determine the amount of water and propene that can be formed.
First, calculate the moles of propanol (C3H7OH) using its molar mass. Then, use the balanced chemical equation for the combustion reaction of propanol to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass to find the mass produced.
C3H8O ==== Count them.
C3H8O ==== Count them.
To find the grams of H2O and C3H6 formed from 6g of C3H8O, first calculate the molar mass of C3H8O: 44.1 g/mol. Then, using the stoichiometry of the reaction yielding H2O and C3H6 from C3H8O, you can determine the grams produced. The balanced reaction is C3H8O -> H2O + C3H6, and for every 1 mol of C3H8O, you get 1 mol of H2O and 1 mol of C3H6. So, 6g of C3H8O yields 6g of H2O and 6g of C3H6.
The structural formulas for the propyl alcohol isomers are as follows: n-propyl alcohol (1-propanol): CH3CH2CH2OH or C3H8O Isopropyl alcohol (2-propanol): (CH3)2CHOH or C3H8O These structural formulas represent the arrangement of atoms in the molecule of each isomer.
For 2-propanol, there are 9 fundamental vibrations: 3 translational, 3 rotational, and 3 vibrational modes.
Of course 6 moles.
16 grams of oxygen how many moles is 0,5 moles.
moles of what?