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To find the grams of H2O and C3H6 formed from 6g of C3H8O, first calculate the molar mass of C3H8O: 44.1 g/mol. Then, using the stoichiometry of the reaction yielding H2O and C3H6 from C3H8O, you can determine the grams produced. The balanced reaction is C3H8O -> H2O + C3H6, and for every 1 mol of C3H8O, you get 1 mol of H2O and 1 mol of C3H6. So, 6g of C3H8O yields 6g of H2O and 6g of C3H6.
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How many grams of water and propene can be formed from the reaction of 6.0 grams of 2-propanol?
To determine the amount of water and propene that can be formed, we first need to write out the balanced chemical equation for the reaction of 2-propanol (C3H8O) to form water (H2O) and propene (C3H6): C3H8O -> C3H6 + H2O Next, calculate the molar mass of 2-propanol (60.1 g/mol) and the molar masses of water (18.0 g/mol) and propene (42.1 g/mol). Then, use stoichiometry to convert the mass of 2-propanol to moles, and from there determine the amount of water and propene that can be formed.
How many moles of propanol C3H8O are there in 42.1g of propanol?
To find the number of moles in 42.1g of propanol (C3H8O), divide the given mass by the molar mass of propanol. The molar mass of propanol is 60.1 g/mol (3 carbons with a molar mass of 12.01 g/mol each, 8 hydrogens with a molar mass of 1.01 g/mol each, and 1 oxygen with a molar mass of 16.00 g/mol). So, 42.1g / 60.1 g/mol = 0.70 moles of propanol.
If 5 grams of oxygen combines with 37.2 grams of uranium to form uranium oxide how many grams of the oxide are formed?
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
When the amount of oxygen is limited carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
How many carbon atoms are there in 200 molecules of C3H8O?
200 molecules C3H8O (1 mole C3H8O/6.022 X 10^23)(3 mole C/1 mole C3H8O)(6.022 X 10^23/1 mole C) = 600 molecules of carbon atoms -------------------------------------------- Of course, you can just look at this set up and see there are 600 molecules. My answer set up is a formal set up. ( 200 * 3 would do it )
How many grams of water and propene can be formed from the reaction of 6.0 grams of 2-propanol?
To determine the amount of water and propene that can be formed, we first need to write out the balanced chemical equation for the reaction of 2-propanol (C3H8O) to form water (H2O) and propene (C3H6): C3H8O -> C3H6 + H2O Next, calculate the molar mass of 2-propanol (60.1 g/mol) and the molar masses of water (18.0 g/mol) and propene (42.1 g/mol). Then, use stoichiometry to convert the mass of 2-propanol to moles, and from there determine the amount of water and propene that can be formed.
How many atoms are there in carbon?
C3H8O ==== Count them.
How many carbon atoms are there?
C3H8O ==== Count them.
How many grams of water are formed in a reaction between hydrogen and 25 grams of oxygen?
25
How many moles of CO2 will be produced from 0.33 mol C3H8O in the reaction 2C3H8O plus 9O2 producing 6CO2 and 8H2O?
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
How is molecular formula C3H6 and molecular formula C6H12 related?
Both formulas are possible molecular formulas for the same empirical formula, CH2.
How many moles of propanol C3H8O are there in 42.1g of propanol?
To find the number of moles in 42.1g of propanol (C3H8O), divide the given mass by the molar mass of propanol. The molar mass of propanol is 60.1 g/mol (3 carbons with a molar mass of 12.01 g/mol each, 8 hydrogens with a molar mass of 1.01 g/mol each, and 1 oxygen with a molar mass of 16.00 g/mol). So, 42.1g / 60.1 g/mol = 0.70 moles of propanol.
If 5 grams of oxygen combines with 37.2 grams of uranium to form uranium oxide how many grams of the oxide are formed?
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen qnd 8 grams of oxygen form How many grams of water form?
if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
When the amount of oxygen is limited carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form.. How many grams of water form?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form. How many grams of water form?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
