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Cs = 132.91 g/mol

1 kg = 1000g

595kg x (1000g/1kg) x (1mol/132.91g) = 4476.713566 = 4.48 x 10^3 mol Cs

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595 kg carbon is equal to 49 542 moles.

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C2H6O+3O2>2CO2+3H2O

Q: How many moles of C are contained in 595 kg of C?

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1 kg of difluorodichloromethane is equivalent to 8,27 moles.

12,4439 kg of gold contain 63,177 moles.

The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).

This depends on the specific element or compound.

5.00 kg of Cu is equivalent to 78,68 moles.

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1 kg of difluorodichloromethane is equivalent to 8,27 moles.

1,000 grams = 1.000 kg 595 grams = 0.595 kg

12,4439 kg of gold contain 63,177 moles.

2.70 m = 2.70 moles/kg solvent3250 g solvent = 3.25 kg solvent2.70 moles/kg x 3.25 kg = 8.775 moles NaNO3 = 8.78 moles NaNO3 (3 significant figures)

The answer is 30,151 kg.

15kg is 15000g. 15000/58.12 = 258.087 moles.

1 kg NaCl contain 17,112 moles.

12.3 kg=12,300 g 12,300 g/44.01g (molar mass) = 279.5 moles 279.5 moles x (6.02 x 10^23) = 1.68248 x 10^26 x 2 = 3.366 x 10^26 atoms of Oxygen in CO2

(1kg C2H6O2 )(1000g/1kg)(1mol/62g) = 16.1 moles

The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).

This depends on the specific element or compound.

5.00 kg of Cu is equivalent to 78,68 moles.