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How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
If you have a sample of 4.25 g of strontium hydroxide SrOH2 How many moles of strontium hydroxide are there?
0.0349 mol
How many moles are in 8 grams of sodium hydroxide?
0.2 mol
You have a sample of 1.25 g of magnesium hydroxide MgOH 2 How many moles of magnesium hydroxide are there?
0.0214 mol
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How many moles of potassium hydroxide are required to make 200cm3 of 0.5M solution?
To find the moles of potassium hydroxide in a 0.5M solution, use the formula moles = concentration (M) x volume (L). First, convert 200cm^3 to liters (200cm^3 = 0.2L). Then, calculate moles = 0.5 x 0.2 = 0.1 moles of potassium hydroxide needed to make a 0.5M solution in 200cm^3.
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
How many moles of calcium hydroxide are needed to react with 5.88 mL of nitric acid?
To determine the number of moles of calcium hydroxide needed to react with the nitric acid, you would need to know the concentration of the nitric acid. With the concentration, you can use the balanced chemical equation of the reaction to calculate the moles of calcium hydroxide required.
How many millimoles are in 12g of sodium hydroxide?
The molecular weight of sodium hydroxide is 40g/mol. To get the amount of moles, you have to divide the weight by molecular mass. 12g / 40 is 0.3 moles. This is 300 millimoles.
How many moles of solute do you need to make one liter of a 1.25 molL ammonium hydroxide solution?
You would need 1.25 moles of ammonium hydroxide to make one liter of a 1.25 mol/L solution.
How many moles are in 98.3 molecules of aluminum hydroxide AL(OH)3?
To convert from molecules to moles, divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Therefore, 98.3 molecules of aluminum hydroxide would be approximately 0.163 moles.
How many moles of aluminum hydroxide is 39.0g?
Aluminium hydroxide, Al(OH)3 has molar mass 27.0+3(17.0) = 78.0Amount of Al(OH)3 = 39.0/78.0 = 0.500molThere are 0.5 moles of aluminium hydroxide in a 39.0g pure sample.
