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Balanced equation first.

2Al + 6HCl >> 2AlCl3 + 3H2

(find limiting reactant )

5 mole Al (6 mole HCl/2mole Al) = 15 mole HCl

5 mole HCl (2 mole Al/6 mole HCl) = 1.7 mole Al

( Al looks short of what is required, so will drive reaction )

5 moles Al (3 moles H2/2 moles Al)

= 7.5 moles of H2 produced.

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Wiki User

13y ago
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13y ago

Balanced equation first.

Cl2 + H2 >> 2HCl

Now use PV = nRT to find moles Cl2 as this limits and drives reaction.

(1 atm)(5.00 L) = n(0.08206 Latm/molK)(298.15 K)

= 0.204 moles Cl2 ( now use stoichiometry )

0.204 moles Cl2 (2mole HCl/1 mole Cl2)

= 0.408 moles HCl produced

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Wiki User

10y ago

The reaction between HCl & Al will be follow as :

6HCl + 2Al = 2AlCl3 + 3H2

Now 2 mole of Al reacts with = 6 moles of HCl

Then 0.06591 moles of Al will react with = 3X0.06591 = 0.19773 mole of HCl

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3y ago

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Q: Calculate the number of moles of hydrogen gas produced when 5.0 moles of aluminum metal react with 5.0 moles of HCl?
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