answersLogoWhite

0


Best Answer

Ok, so we have... Zn + CuCl2 -> ZnCL2 + Cu

And we are given that we have 28g of Zn (Zinc).

But the question calls for moles of ZnCl2.

So, the first step is to convert grams to moles of Zn.

We will need to find the AMU (Atomic Mass Units) that a Zn atom's mass.

A Zn atom has a mass of 63.546 AMU.

Now, we take the given mass and divide it by the mass of the atom to get the moles of reactant we have.

28g/63.546AMU≈ .4406257moles

If your teacher/ professor cares about sig figs, then it's .44 because you only have two sig figs from the given from the given mass of Zn (28g).

Now, the easy part.

What is the ratio of Zn atoms on the reactant side to Zn atoms on the product side?

1:1

And since we have excess CuCl2 Nothing else limits the reaction.

So, .44 (or how ever far your teacher wants you to round) moles of Zn reactants in a ideal environment (you will learn later that no reaction is 100% and that there are reactants always left over and how to solve for that) produces .44 moles of ZnCl2.

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many moles of ZnCl2 will be produced from 28g of Zn assuming CuCl2 is available in excess?
Write your answer...
Submit
Still have questions?
magnify glass
imp