The complete decomposition reaction is as follows:
2 BrF3 → Br2 + 3 F2 , so 2 moles BrF3 will give 1 mole Br2 , hence 0.248 mole gives 0.124 mole Br2
The atoms in the reacts are always present in the products. There is one mole of bromine per molecule and .196 moles of the molecule. Thus, there will be .196 mols of bromine present after the reaction.
Aluminium Bromide = AlBr3
By the reaction of Pure Boron with Fluorine:2 B + 3 F2 ----> 2 BF3
The product of this reaction is gluconic acid.
1-bromo 1 pentene
The atoms in the reacts are always present in the products. There is one mole of bromine per molecule and .196 moles of the molecule. Thus, there will be .196 mols of bromine present after the reaction.
Aluminium Bromide = AlBr3
By the reaction of Pure Boron with Fluorine:2 B + 3 F2 ----> 2 BF3
There is no such compound named Phosphorus bromine. It you refer to the product formed in the reaction of phosphorus and bromine, its Phosphorus Tribromide = PBr3
A bromide is formed.
The reaction of iron(II) salts with bromine is a redox reaction forming iron(III). The aqueous reaction with bromine water is typical:- 2Fe2+ + Br2 -> 2Fe3+ + 2Br- If you started with iron(II) bromide, iron(III) bromide would be formed
2,4,6-tribromophenol is formed by the loss of CO2 (decarbonylation).
The product of this reaction is gluconic acid.
During the elimination reactions of saturated organic compounds double bond (Alkene) or triple bond (Alkyne) is formed to check them add Bromine solution to reaction mixture the decolourization of bromine confirms the elimination reaction
1-bromo 1 pentene
Potassium bromide (KBr) is a white solid formed by the reaction of potassium hydroxide and bromine.
The hydroxyl group in phenol is an activating ortho/para director, but has some slight steric hindrance too ortho position substitution. Therefore, the predominant product of reaction between phenol and bromine will be 4-bromophenol, if reaction conditions are carefully controlled. With excess bromine, di- and tri-bromo phenols will be formed.