One mol of copper is 6.02 x1023 atoms.
So 3.44 x 1023 would be 0.571 moles.
The equivalent number of moles is 0,57.
20034
556899
1.20x10^24 atoms x 1 mole/6.02x10^23 atoms = 1.99 moles
Take that number of copper atoms and divide by "Avogadro's constant," which is the number of representative particles (in this case, atoms) in 1 mole of any substance. Here's the math: 1.8x10e24 / 6.02x10e23 = approximately 3 moles.
From the density and volume, the mass of this amount of copper is 8.96 grams. There are 63.546 grams in 1 mole of copper, so this is 0.141 moles. There are 6.023 x 10²³ atoms in 1 mole. Multiply this by 0.141 moles = 8.492 x 10²² atoms.
6.02 X 1023 particles per mole X .75 moles = 4.52 X 1023 molecules.
2.11x10^24 atoms... Divide by Avogadro's Constant (6.02x10^23 particles/mole) Gives you moles of copper... Multiply by the molar mass of copper. (?? g/mol) Gives you grams of copper...
4,5 moles of copper are equivalent to 285,957 g.
1.20x10^24 atoms x 1 mole/6.02x10^23 atoms = 1.99 moles
Approx. 10e-17 moles.
5 mole copper (6.022 X 1023/1 mole Cu) = 3 X 1024 atoms of copper -----------------------------------
This is equivalent to 1,4 moles.
The number of copper atoms is 79,49.10e23.
(1.2 x 1048)/Avogadro's number = 2.0 X 1024 moles. (I hope the questioner has a large storehouse!)
5 moles of helium He atoms is equivalent to 20,013 g.
1,0.10e9 atoms is equivalent to 0,166.10e-14 moles.
3,2x10e22 atoms of sulfur is equivalent to 0,053 moles.
The formula for converting is: atoms ÷ Avogadro's constant = # moles (1.8 × 1023) ÷ (6.02 × 1023)= 0.299 moles Cu
Take that number of copper atoms and divide by "Avogadro's constant," which is the number of representative particles (in this case, atoms) in 1 mole of any substance. Here's the math: 1.8x10e24 / 6.02x10e23 = approximately 3 moles.