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Balanced equation.

2Fe + 3Br2 -> 2FeBr3

need limiting reactant; suspect iron

9.20 mole Fe (3 mole Br2/2 mole Fe) = 13.8 moles

the stated iron moles are not nearly this much; iron limits and drives the reaction

looks one to one, so................

9.20 moles Fe (2 moles FeBr3/ 2mole Fe)

= 9.20 moles FeBr3 produced

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Q: How many moles of product are formed when 9.20 moles of iron III react with bromine gas?
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