If you consider also the starting point, then 3. Otherwise, 2.
In a binary tree with a maximum depth of ( H ), the number of leaf nodes can vary depending on the structure of the tree. However, if the tree is a complete binary tree, the maximum number of leaf nodes occurs at depth ( H ), which is ( 2^H ). For a full binary tree, the minimum number of leaf nodes at depth ( H ) is ( 1 ), occurring when all nodes except the last level are filled. Thus, the number of leaf nodes can range from ( 1 ) to ( 2^H ).
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if u assign a 0th level to root of binary tree then,the minimum no. of nodes for depth K is k+1.
Complete Binary tree: -All leaf nodes are found at the tree depth level -All nodes(non-leaf) have two children Strictly Binary tree: -Nodes can have 0 or 2 children
Complete Binary tree: All leaf nodes are found at the tree depth level and All non-leaf nodes have two children. Extended Binary tree: Nodes can have either 0 or 2 children.
A full binary tree of depth 3 has at least 4 nodes. That is; 1 root, 2 children and at least 1 grandchild. The maximum is 7 nodes (4 grandchildren).
Use the following formula: (2^n)-1. E.g., if the depth is 3, the number of nodes is (2^3)-1 = 8-1 = 7. Note that 7 is the maximum number of nodes, not the actual number of nodes. To count the actual nodes you must traverse the tree, updating an accumulator as you go.
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2^(d+1) - 1
tell me , how we create a username & password for many users in c language.
If N>1, there are (2N-1) - (2N-1-1), otherwise, 1 nodes in the Nth level of a balanced binary tree.
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