How many molecules of water are present in 36.0 g of H2O?

Answer 1

36 g (6.02 x 1023 at / 12.01 g) = 1.8 x 1024atoms

Answer 2

To find the number of molecules in 36.0 g of H2O, you first need to convert the grams to moles using the molar mass of water (18.015 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.

Answer 3

36 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O)

= 1.2 X 1024 molecules of water

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Answer 4

1 mole H2O = 18.0g = 6.022 x 1023 molecules

36.0g H2O x (6.022 x 1023 molecules)/(18.0g) = 1.20 x 1024 molecules H2O

Answer 5

36 gram H2O = 2 mol = 2 * 6*10^23 molecules H2O = 12*10^23 * 3 (atoms per molecule) = 3.6*10^24 atoms

Answer 6

36 g = 2 moles = 1.2044 x 1024 molecules

Answer 7

24

Answer 8

6