It's 1.5 M
No, adding water to a solution does not change the molarity of the solute. The molarity of a solution is calculated using the amount of solute and the volume of the solution, so diluting with water only changes the volume, not the amount of solute present.
The final volume of the solution is 375 mL (125 mL HCl + 250 mL water). As the water does not contribute to the molarity of the solution, the moles of HCl remain the same. Thus, the molarity of the final solution is 0.251 mol / (0.375 L) = 0.670 M.
0.1 M NaOH is prepared by dissolving sodium hydroxide (NaOH) pellets or flakes in water to make a 0.1 molar solution. This means there are 0.1 moles of NaOH dissolved in 1 liter of water. The molarity of the solution is calculated using the formula: Molarity = moles of solute / liters of solution.
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
No, adding water to a solution does not change the molarity of the solute. The molarity of a solution is calculated using the amount of solute and the volume of the solution, so diluting with water only changes the volume, not the amount of solute present.
The final volume of the solution is 375 mL (125 mL HCl + 250 mL water). As the water does not contribute to the molarity of the solution, the moles of HCl remain the same. Thus, the molarity of the final solution is 0.251 mol / (0.375 L) = 0.670 M.
0.1 M NaOH is prepared by dissolving sodium hydroxide (NaOH) pellets or flakes in water to make a 0.1 molar solution. This means there are 0.1 moles of NaOH dissolved in 1 liter of water. The molarity of the solution is calculated using the formula: Molarity = moles of solute / liters of solution.
Vinegar is a dilute solution of acetic acid and is created by diluting concentrated acetic acid 20 fold to create a 5% acid solution.
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
The molarity of a 5% solution of NH3 in water depends on the density and molecular weight of NH3. Without this information, it is not possible to calculate the molarity.
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
The molarity of the solution can be calculated by dividing the moles of solute by the volume of solution in liters. In this case, 2 moles of NaOH in 1620 mL (1.62 L) of water gives a molarity of approximately 1.23 M.
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
The molarity is 2 mol/L.
7M
The molarity of sweet tea depends on the amount of solute (sugar) dissolved in the solution. If you know the amount of sugar added to a specific volume of tea, you can calculate the molarity using the formula: Molarity (M) = moles of solute / liters of solution.