0
Answer is, I think, 6 factorial, usually written 6!, which means 6x5x4x3x2x1, which is 120. This is the total number of different combinations of 6 digits. This answer is true if all six digits are always used. If it is allowed to use not all 6 digits, then the answer would be 6!+5!+4!+3!+2!+1!
This is 620+120+24+6+2+1, or 773.
Am I right? I left school 37 years ago, did maths A level in the UK but most of it is now forgotten!
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
How many decimal numbers can be represented by 4-bits?
There are 16 decimal numbers that can be represented by 4-bits.
How many bits are required in decimal numbers in range 0 to 999 using Straight binary code and BCD code?
10 bits would be required. 10 bits long (10 digits long) can represent up to 1024.
How many numbers can you represent with 4 bits?
16 of them.
How many characters can be represented using 8 bits?
8 bits = 64 character
How many different numbers can be represented by 3 bits?
1000
How many binary bits are necessary to represent 748 different numbers?
Binary bits are necessary to represent 748 different numbers in the sense that binary bits are represented in digital wave form. Binary bits also have an exponent of one.
How many words did shakespeare put into the dictionary?
It depends which dictionary, doesn't it? Shakespeare was responsible for inventing many words which were not previously recorded, and for using many words in ways not previously recorded. Estimates of the numbers vary.
How many numbers can be stored in 8 bits?
256 (0 through 255)
How many bytes and how many bits does the word duck contain?
If you are using the ASCII system, the word "duck", as it has four letters, contains 4 bytes, or 32 bits.
How many bits a 8085 can process at a same time?
Generally, 8 bits at a time. Some instructions deal with 16 bit numbers.
How many binary number combinations using 6 bits?
Each bit can be on or off giving 2 possible states, and for each bit the other bits can be in either state; so there are 2 x 2 x 2 x 2 x 2 x 2 = 26 = 64 possible numbers (which can either represent 0 to 63 or -32 to +31 using signed numbers).
How many decimal numbers can be represented by 8-bits?
256 in total - including zero.
