Want this question answered?
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
You probable think to sodium sulfate, Na2SO4. Na2SO4 has: 7 atoms total - 2 sodium, 1 sulfur and 4 oxygen. 2Na2SO4 (two molecules) have 14 atoms.
Each formula unit dissociates into two sodium ions and one sulfate ion, for a total of 3.
Not much. You get a buffer solution. There is no reaction except if the relative concentrations of the two are different from each other, in which case the acid will protonate the sodium salt or the sodium salt with deprotonate the acid depending on how you want to think about it.
In solid state at normal temperature the don't react with each other because both have the stable crystal structures but in aqueous solutions when they are allow to mixed white precipitate of silver sulphate are formed because its solubility is very low in water, 2AgNO3(Aq.) + Na2SO4 -----> Ag2SO4 (Ppts.) + Ag+ + NO3-The balanced equation above is incorrect and miss Na all together.Both sodium sulfate and silver nitrate are soluble in water. If I swap the names I get silver sulfate and sodium nitrate. Silver sulfate is insoluble and sodium nitrate is soluble. So if I mix a solution of sodium sulfate and a solution of silver nitrate, an insoluble precipitate of silver sulfate will form and sodium nitrate will remain in solution. Two go into solution, and one comes out. The balanced equation is:Na2SO4(aq) + 2 AgNO3(aq) = Ag2SO4(s) + 2 NaNO3(aq)
It means that only one atom of the element exist in a single molecule of the compound. For example, Sodium sulfate, Na2SO4 , has 2 sodium atoms, 1 sulfur atom and 4 oxygen atoms. It is supposed to be Na2S1O4, but the former is more commonly used.
Each sodium will transfer 1 electron. So, for NaCl, one electron is transferred. In Na2SO4 (sodium sulfate), 2 electrons will be transferred (1 electron from each sodium).
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
You probable think to sodium sulfate, Na2SO4. Na2SO4 has: 7 atoms total - 2 sodium, 1 sulfur and 4 oxygen. 2Na2SO4 (two molecules) have 14 atoms.
Sulfate consists of 1 S, and 4 O and so has a charge of 2-. You can see this directly from the periodic table by checking what group these atoms are in. Sulfur and Oxygen are both in the 6th group, meaning they both have 6 valence electrons. So (6 electrons * 5 atoms) = 30 electrons. If we follow the octet rule (each atom must have 8 valence electrons for a full octet), then we need 2 more electrons. Sodium, Na, is in the 1st group on the periodic table, and therefore has 1 valence electron. So we need 2 sodium atoms, giving us the formula: Na2SO4 That is, 2 Na 1 S 4 O It's important to remember that when atoms 'share' their electrons by bonding, that BOTH atoms 'see' the electrons as theirs, meaning that, for example, although you may have 14 electrons between 2 atoms, as long as there is a single bond between the atoms they will both have full octets. For example: O2 :::O:O::: where : = pair of electrons.
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
Each formula unit dissociates into two sodium ions and one sulfate ion, for a total of 3.
Not much. You get a buffer solution. There is no reaction except if the relative concentrations of the two are different from each other, in which case the acid will protonate the sodium salt or the sodium salt with deprotonate the acid depending on how you want to think about it.
In solid state at normal temperature the don't react with each other because both have the stable crystal structures but in aqueous solutions when they are allow to mixed white precipitate of silver sulphate are formed because its solubility is very low in water, 2AgNO3(Aq.) + Na2SO4 -----> Ag2SO4 (Ppts.) + Ag+ + NO3-The balanced equation above is incorrect and miss Na all together.Both sodium sulfate and silver nitrate are soluble in water. If I swap the names I get silver sulfate and sodium nitrate. Silver sulfate is insoluble and sodium nitrate is soluble. So if I mix a solution of sodium sulfate and a solution of silver nitrate, an insoluble precipitate of silver sulfate will form and sodium nitrate will remain in solution. Two go into solution, and one comes out. The balanced equation is:Na2SO4(aq) + 2 AgNO3(aq) = Ag2SO4(s) + 2 NaNO3(aq)
Sodium bicarbonate has: 1 sodium atom, 1 hydrogen atom, 1 carbon atom, 3 oxygen atoms.
The sodium cation is positive (+1).
The sodium atom loses its valence electron to the chlorine atom forming a positive sodium ion and a negative chloride ion. The two are attracted to each other because of their opposite charges.