In one molecule of sodium sulfate, there are 2 sodium atoms (Na), 1 sulfur atom (S), and 4 oxygen atoms (O).
Sodium sulfate has the molecular formula Na2SO4. This is because sodium has a net charge of +1 and SO4 has a net charge of -2.
The chemical formula for sodium sulfate is Na2SO4. It consists of two sodium atoms, one sulfur atom, and four oxygen atoms. The subscript numbers indicate the number of each type of atom present in the compound.
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
There would be no reaction because all possible outcomes are soluble in water, and if it did react your products would be the same as the reactants because you have sulfate on both of the reactants.
You probable think to sodium sulfate, Na2SO4. Na2SO4 has: 7 atoms total - 2 sodium, 1 sulfur and 4 oxygen. 2Na2SO4 (two molecules) have 14 atoms.
Sodium sulfate has the molecular formula Na2SO4. This is because sodium has a net charge of +1 and SO4 has a net charge of -2.
The chemical formula for sodium sulfate is Na2SO4. It consists of two sodium atoms, one sulfur atom, and four oxygen atoms. The subscript numbers indicate the number of each type of atom present in the compound.
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
It means that only one atom of the element exist in a single molecule of the compound. For example, Sodium sulfate, Na2SO4 , has 2 sodium atoms, 1 sulfur atom and 4 oxygen atoms. It is supposed to be Na2S1O4, but the former is more commonly used.
Each sodium will transfer 1 electron. So, for NaCl, one electron is transferred. In Na2SO4 (sodium sulfate), 2 electrons will be transferred (1 electron from each sodium).
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
Sulfate consists of 1 S, and 4 O and so has a charge of 2-. You can see this directly from the periodic table by checking what group these atoms are in. Sulfur and Oxygen are both in the 6th group, meaning they both have 6 valence electrons. So (6 electrons * 5 atoms) = 30 electrons. If we follow the octet rule (each atom must have 8 valence electrons for a full octet), then we need 2 more electrons. Sodium, Na, is in the 1st group on the periodic table, and therefore has 1 valence electron. So we need 2 sodium atoms, giving us the formula: Na2SO4 That is, 2 Na 1 S 4 O It's important to remember that when atoms 'share' their electrons by bonding, that BOTH atoms 'see' the electrons as theirs, meaning that, for example, although you may have 14 electrons between 2 atoms, as long as there is a single bond between the atoms they will both have full octets. For example: O2 :::O:O::: where : = pair of electrons.
There would be no reaction because all possible outcomes are soluble in water, and if it did react your products would be the same as the reactants because you have sulfate on both of the reactants.
You probable think to sodium sulfate, Na2SO4. Na2SO4 has: 7 atoms total - 2 sodium, 1 sulfur and 4 oxygen. 2Na2SO4 (two molecules) have 14 atoms.
The anion (SO4)2- is divalent; the cation Na+ is monovalent.
HCl + NaOH --> Na2SO4 + H2O You're missing something there... There's sulfur in the products but not in the reactants. And chloride in the reactants but not in the products... More likely you meant HCl + NaOH --> NaCl + H2O Which is already balanced.
In solid state at normal temperature the don't react with each other because both have the stable crystal structures but in aqueous solutions when they are allow to mixed white precipitate of silver sulphate are formed because its solubility is very low in water, 2AgNO3(Aq.) + Na2SO4 -----> Ag2SO4 (Ppts.) + Ag+ + NO3-The balanced equation above is incorrect and miss Na all together.Both sodium sulfate and silver nitrate are soluble in water. If I swap the names I get silver sulfate and sodium nitrate. Silver sulfate is insoluble and sodium nitrate is soluble. So if I mix a solution of sodium sulfate and a solution of silver nitrate, an insoluble precipitate of silver sulfate will form and sodium nitrate will remain in solution. Two go into solution, and one comes out. The balanced equation is:Na2SO4(aq) + 2 AgNO3(aq) = Ag2SO4(s) + 2 NaNO3(aq)