In solid state at normal temperature the don't react with each other because both have the stable crystal structures but in aqueous solutions when they are allow to mixed white precipitate of silver sulphate are formed because its solubility is very low in water, 2AgNO3(Aq.) + Na2SO4 -----> Ag2SO4 (Ppts.) + Ag+ + NO3-
The balanced equation above is incorrect and miss Na all together.
Both sodium sulfate and silver nitrate are soluble in water. If I swap the names I get silver sulfate and sodium nitrate. Silver sulfate is insoluble and sodium nitrate is soluble. So if I mix a solution of sodium sulfate and a solution of silver nitrate, an insoluble precipitate of silver sulfate will form and sodium nitrate will remain in solution. Two go into solution, and one comes out. The balanced equation is:
Na2SO4(aq) + 2 AgNO3(aq) = Ag2SO4(s) + 2 NaNO3(aq)
The spectator ions in the reaction between silver sulfate and barium nitrate are nitrate (NO3-) ions and sulfate (SO4^2-) ions. These ions do not participate in the formation of the precipitate (barium sulfate) and remain unchanged throughout the reaction.
Hydrated sodium, sulfate, silver, and nitrate ions. (The ions already exist in the sodium sulfate and silver nitrate solids, but may not be hydrated there.) since silver sulfate is not very soluble in water, most of the silver and sulfate ions will be removed from the water as solid precipitate, but some hydrated ions will remain in solution.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
When barium nitrate and sodium sulfate mix, they form barium sulfate and sodium nitrate. Barium sulfate is a white solid that precipitates out of the solution, while sodium nitrate remains dissolved. This reaction can be used in chemistry labs to demonstrate precipitation reactions.
Barium nitrate and sodium sulfate react to form barium sulfate and sodium nitrate in a double displacement reaction. This reaction results in the formation of a white precipitate of barium sulfate, which is insoluble in water.
The spectator ions in the reaction between silver sulfate and barium nitrate are nitrate (NO3-) ions and sulfate (SO4^2-) ions. These ions do not participate in the formation of the precipitate (barium sulfate) and remain unchanged throughout the reaction.
Hydrated sodium, sulfate, silver, and nitrate ions. (The ions already exist in the sodium sulfate and silver nitrate solids, but may not be hydrated there.) since silver sulfate is not very soluble in water, most of the silver and sulfate ions will be removed from the water as solid precipitate, but some hydrated ions will remain in solution.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
When barium nitrate and sodium sulfate mix, they form barium sulfate and sodium nitrate. Barium sulfate is a white solid that precipitates out of the solution, while sodium nitrate remains dissolved. This reaction can be used in chemistry labs to demonstrate precipitation reactions.
If the sodium sulfate and barium nitrate are both in solution in water, a precipitate of barium sulfate will be formed, because this salt is much less soluble in water than barium nitrate, sodium sulfate, or sodium nitrate.
When sodium nitrate and silver nitrate are mixed, no reaction occurs. These compounds do not react with each other to form a new compound. Sodium nitrate remains as sodium nitrate and silver nitrate remains as silver nitrate when they are mixed together.
When sodium iodide reacts with silver nitrate, a double displacement reaction occurs. The sodium ions exchange with the silver ions, forming silver iodide as a white precipitate and sodium nitrate. This reaction can be represented by the equation: 2NaI + 2AgNO3 → 2AgI + 2NaNO3
Barium nitrate and sodium sulfate react to form barium sulfate and sodium nitrate in a double displacement reaction. This reaction results in the formation of a white precipitate of barium sulfate, which is insoluble in water.
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When silver nitrate reacts with sodium bicarbonate, a white precipitate of silver carbonate forms along with sodium nitrate and water. This reaction can be written as: AgNO3 + NaHCO3 -> Ag2CO3 + NaNO3 + H2O.
No reaction will occur between Potassium Sulfate and Ammonium Nitrate.
The reaction between silver nitrate and sodium chloride forms silver chloride and sodium nitrate. The balanced equation is: AgNO3 + NaCl → AgCl + NaNO3