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The size of Betelgeuse is variable (it pulsates); plus, there are different estimates. But its diameter is approximately 900 times that of our Sun, which in turn is roughly 100 times the diameter of Earth (actually 109, but the data don't justify a very exact calculation), so Betelgeuse has roughly 900 x 100 = 90,000 times the DIAMETER of Earth; the ratio of volumes is that same number, cubed, or (after some rounding) about 700,000,000,000,000 times as much.
4 moons would go across the earth, and 109 earths would go across the sun.
If the star Betelgeuse replaced the Sun, most planets will be inside the star, even Jupiter. It would outshine the Sun like the Sun outshines the Moon.
The Earth is larger than the moon, and therefore only a fraction (1/50) of the Earth would theoretically "fit" inside the space of the moon. Therefore, 50 moons could fit inside the Earth.
The star Betelgeuse is estimated to be about 1000 times the diameter of the Sun.If you put Betelgeuse where the Sun is; the planets Mercury, Venus, Earth and Mars would all be inside the star.
12742 km / 3474 km = 3.67
A lunar eclipse
Approximately 72 million Earth moons could fit inside the sun.
Yes. The moons size is 1/6th of earths so it can fit in the earth.
No the Earth would pull u more than the moon
Your would weigh 1/6th as much as you do here on mother Earth. The how is our moons' mass, and therefore its' gravity, is about 1/6 as much as the Earths'. Its' gravity well is not as deep as the Earths.
approximately 109 earths would fit around the circumference of the sun