The reaction is :-
2C2H6 + 7O2 ----------> 4CO2 + 6H2O
When one mole ethane is combusted 7/2 moles of oxygen are used.
When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used.
No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
3 moles x 6.02x10^23 molecules/mole = 1.8x10^24 molecules
90.21
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
2.45 X 1023 molecules CH2 (1 mole CH2/6.022 X 1023)= 0.407 moles CH2============
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
6,022140857.1023 molecules---------------------------------------------1 mole2.1022 molecules--------------------------------------------------------------x molex = 0,033 moles
The equivalent is 1,6.10e-15 moles.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
2.01 mol
The answer is 15 moles.
1 mole=6.02*1023 molecules or atoms5.23 moles=6.02*1023 * 5.23= {[(3.14846*1024molecules)]}
First calculate the moles of methanal(formaldehyde) moles(HCHO)= 0.11 / (30; Mr of ethanal) = 0.0036666... Remember the Avogadro Number. (6.022 x 10^(23)) is the number of molecules/atoms in ONE mole . Hence in 0.0036666 moles there are 0.0036666... X 6.022 x 10(23) = 2.20806 x 10^(21) molecules in 0.11 g of methanal. NB ; In modern IUPAC chemical nomenclature formaldehyde is named as METHANAL. NNB Note the 'A' instead 'o' in the name, NNNB The aldehyde formula is written as HCHO ; ( Ethanal would be CH3CHO). The arrangement of the letters in the formula is XCHO Hope that helps!!!!
There are 1.5 moles water in 27 grams
2.45 X 1023 molecules CH2 (1 mole CH2/6.022 X 1023)= 0.407 moles CH2============
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
4.651024 molecules of NO2 equals 7,721 moles.
23 moles of oxygen contain 138,509.10e23 molecules.
0.175 X Avogadro's Number = about 1.05 X 1023.