Type your answer here... 2 × (6.02 × 1023)
There are 6.022 x 10^23 atoms of chlorine in 1.00 mol of chlorine gas, as Avogadro's number tells us that 1 mole of any substance contains that many atoms.
To find the number of atoms of He gas in 0.268 g, first calculate the moles of He using the molar mass of He (4.0026 g/mol). 0.268 g / 4.0026 g/mol ≈ 0.067 mol of He. Then, use Avogadro's number (6.022 x 10^23) to find the number of atoms: 0.067 mol x 6.022 x 10^23 atoms/mol ≈ 4.03 x 10^22 atoms of He gas in 0.268 g.
0.251 moles neon (6.022 X 1023/1 mole Ne) = 1.51 X 1023 atoms of neon -------------------------------------
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
The answer is 18,061.1023 atoms.
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
48,177 134 32.1023 atoms
There are 0.45 mol of BaSO4. In one mole of BaSO4, there is one sulfur atom. Therefore, there are 0.45 mol of sulfur atoms in 0.45 mol of BaSO4.
Avagadro's number = 6.022 × 1023 atoms/mol0.5 mol × (6.022 × 1023) atoms/mol = 3.011 ×1023 atoms
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
107,43.10e+23 atoms