6.023 X 1023 particles make up a 1M solution.
To make a 2 molar solution of hydrochloric acid, you would need to know the volume of the solution you want to make. Once you have the volume, you can use the molarity formula (M = moles of solute / liters of solution) to calculate the grams of hydrochloric acid needed.
Calcium sulfate is very low soluble in water - 2,1 g/L at 20 0C.
You need 841,536 g NaCl.
As many as you like, depending on what you want the concentration to be. (Solubility will eventually become a factor, but sodium hydroxide is pretty darn soluble.)
To make a 1 molar solution of glucose (C6H12O6) in 1 liter of water, you would need to dissolve 180 grams of glucose. This is because the molar mass of glucose is 180 g/mol, so 1 mole of glucose weighs 180 grams.
The molecular weight of NaCl is 58.44; sodium =22.99; Chlorine=35.45. A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.
To calculate the number of moles of particles present in a sample, you need to divide the sample's mass by the molar mass of the particles. If you specify the particles as N'O, you should provide the molar mass of N'O for an accurate calculation.
1400 moles.
To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.
290 grams
Magnesium chloride has a molecular weight of 95.2, so 1 litre of 1 molar MgCl2 would have 95.2g. A 2.5 molar solution would have 2.5X95.2g per litre = 238grams
The molecular weight of NaCl is 58.44; sodium =22.99; Chlorine=35.45. A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.