16 nigg3rs
In our Universe, EM radiation can only come in discrete chunks called "photons." The energy of each individual photon depends on the frequency of the EM radiation. Frequency depends on wavelength (or vice-versa): the shorter the wavelength, the higher the frequency. Thus, short wavelength photons have more energy. That's just how our Universe operates, whether or not we like it.
Frequencies and wavelengths (APEX)
No. Infrared (IR) light is longer wavelength (lower frequency) light and is of lower electromagnetic energy than shorter wavelength (higher frequency) ultraviolet (UV) light. Note that our skin "senses" infrared light (which we normally think of as heat) in a different way than it does ultraviolet light. This may account for the difference in the way it "feels" when we're exposed to light of the two energies. To be clear, ultraviolet light has higher energy photon for photon than infrared light. If both are absorbed by the skin, the reaction of the skin will be slightly different, but the energy imparted to the skin will be greater with the UV light that the IR light.
Each photon has ( h · f ) joules of energy.( ' h ' is Planck's Konstant. ' f ' is the frequency of the radiation.)In order to collect 1 mJ of energy from the radiation, you have to gather up(0.001)/( h · f ) photons. ' h ' is Planck's Konstant, 6.63 x 10-34 joule-second.' f ' is the frequency of the radiation, which is not given in the question.
im 75% positive that it does penetrate deeper than infrared radiation.
yes, x ray radiation photons have more energy than infrared waves
Visible radiation: 370-750 nm. Infrared radiation: 750 nm-300 μm These wavelenghts are not long.
visible and invisible light
The electromagnetic force is transmitted by particles called photons, which are the carriers of electromagnetic radiation. Photons travel at the speed of light and interact with charged particles to create the electromagnetic force.
Radiates it (mainly as infrared photons).
"Laser" is a device that's used to generate very pure electromagnetic radiation,at one single frequency and with all of its photons vibrating in the same directionat the same time.Many different frequencies can be generated by different types of lasers.Infrared radiation is just one of them.
In our Universe, EM radiation can only come in discrete chunks called "photons." The energy of each individual photon depends on the frequency of the EM radiation. Frequency depends on wavelength (or vice-versa): the shorter the wavelength, the higher the frequency. Thus, short wavelength photons have more energy. That's just how our Universe operates, whether or not we like it.
Photons are not difficult to detect because they interact with detectors in a predictable way. Photons can be detected through photoelectric effect, Compton scattering, or by producing electron-positron pairs in certain materials. These interactions allow scientists to detect and measure photons in experiments.
Frequencies and wavelengths (APEX)
Each photon has ( h · f ) joules of energy.( ' h ' is Planck's Konstant. ' f ' is the frequency of the radiation.)In order to collect 1 mJ of energy from the radiation, you have to gather up(0.001)/( h · f ) photons. ' h ' is Planck's Konstant, 6.63 x 10-34 joule-second.' f ' is the frequency of the radiation, which is not given in the question.
No. Infrared (IR) light is longer wavelength (lower frequency) light and is of lower electromagnetic energy than shorter wavelength (higher frequency) ultraviolet (UV) light. Note that our skin "senses" infrared light (which we normally think of as heat) in a different way than it does ultraviolet light. This may account for the difference in the way it "feels" when we're exposed to light of the two energies. To be clear, ultraviolet light has higher energy photon for photon than infrared light. If both are absorbed by the skin, the reaction of the skin will be slightly different, but the energy imparted to the skin will be greater with the UV light that the IR light.
Energy (E) of photons of electromagnetic radiation is given by Planck's equation ..E = hf .. h = Planck constant (6.625^-34 Js), f = frequency (Hz)So E is proportional to frequency .. radiation with the highest frequency is Gamma