it depends on how big the files are. for example a picture could be 200Kb. 1000Kb is 1MB, so 44MB = 44,000KBs. if each picture is 200KB then its simple maths. 44,000/200 = 220 pictures. if the pictures were 1mb each in size then 44mb of space would hold 44 pictures. if they were 4kb each, it would hold 11,000 pictures etc. :)
With the assumption that each picture taken by the camera is 4 Mb, 32 Mb of memory can save a few pictures. It can only save 8 pictures.
Depends on the Type of Image Format you are using to click the pictures !! If you are clicking pictures from phone that too from a 5 MP camera, it can hold on 200+ pictures !!
Approx. 55 pictures. Varies by camera slightly.
It depends on the size of the pictures. It can hold over a hundred pictures if the pictures are smaller than 150 kb. A 100kb picture size: 550 x 349 - 100k - jpg
60000
A high quality image (1028x768) is about 800-900 KB. A MB is 1000 KB, and a GB is 1000 MB. I would say over 10000 pictures.
Approx 64 pics
No, a 4MB flash drive will only hold about two average sized pictures. Documents vary in size a by huge amounts so it is hard to tell but it would probably not hold more than 20 documents. A 4GB flash drive(there is an enormous difference between megabyte and gigabyte) will hold about 2000 average sized pictures though.
it depends on how big the files are. for example a picture could be 200Kb. 1000Kb is 1MB, so 44MB = 44,000KBs. if each picture is 200KB then its simple maths. 44,000/200 = 220 pictures. if the pictures were 1mb each in size then 44mb of space would hold 44 pictures. if they were 4kb each, it would hold 11,000 pictures etc. :)
It depends on the format. In JPEG, it's around 18.
Well first that must be a lot of many and Think of it this way, It will hold up to 1000 hours worth of video or about 200,000 songs or a combination of the two. i hope this helped
Is this a trick question? Assuming that only integral number of pictures can be put on the CD, you can put 0 pictures, since the CD isn't big enough to hold even one picture.