How many points are awarde if two reds are potted in one shot in snooker?

Answer 1

ONE point is scored for each red potted on a single stroke, therefore two points would be scored if two reds are potted in one shot (You could pot all fifteen reds and receive fifteen points, although I would not recommend it - see later) The exception to this would be in the case of a free ball being awarded. If a player fouls and leaves his opponent snookered, the referee awards the incoming player a 'free ball'. This means they can nominate a colour as a red (value one point, whatever the colour) and pot it as one would a red, following it with a colour etc. The difference is that if the player were to pot the 'free ball' (as a red) and ANOTHER red in the same stroke, he would only receive ONE point for the ball on, in this case the 'free ball'. He may also use the 'free ball' to pot ANOTHER red in a cannon, thereby receiving one point, as the potted red would also be a ball that was 'on' (an object ball). Any 'free ball' is re-spotted after potting as the colours stay on the table until all the reds are gone. It's actually a disadvantage to the player in stroke to pot more than one red at a time, as by doing so, he robs himself of points that could have been made with an accompanying colour. I once saw the inimitable Alex Higgins make a three red combination in a championship match in which the balls were at least a foot apart. I also once saw FOUR reds potted in a single shot and it was not a trick shot. I hope this answers your question.