start with the 100's place
0 = 0+0
1 = 1+0 = 0+1
2 = 1+1=2+0=0+2
3 = 3+0 = 2+1 = 1+2 = 0+3
...
with the 100's digit, the number of such numbers is one greater than that number
0 : 1
1 : 2
...
therefore there are 1+2+3+4+5+6+7+8+9+10 = 5*11 = 55 such numbers
unless you don't count 000 as a three digit number, then there are 54 such numbers.
-48
There are one thousand. Starting at 2000 and going to 2999
-22
1 x 10 x 10 x 10 x 9 = 9000 1 = it must be 2 10's = any digits 9 = any digit BUT zero
Select all the numbers that $4221462$ is divisible by.
54
18 positive integers and 36 integers (negative and positive)
There are 320 such numbers.
90
44
1339
There are 10 one digit positive integers (0 - 9) and 9 one digit negative integers (-9 to -1) making 19 in all.
the range of three-digit integers is from 100 to 999. Therefore, there are 300 positive three-digit integers that are divisible by neither 2 nor 3.1 day ago
the answer would be 900
4
there are 999 - 100 + 1 = 900 positive triple digit positive integers, between 100 and 999.(e.g. there are 102 - 100 + 1 = 3 triple digit integers between 100 and 102,namely 100, 101 and 102.)multiply that by 2 to take in consideration of the negative integers,you have 1800 triple digit integers.
Positive integers are greater than negative integers. For positive integers: * The integer with more digits is larger. * If two integers have the same length, compare the first digit. If the first digit is the same, compare the second digit, then the third, etc., until you find a difference. In each case, the integer with the larger digit (at the first position where you find a difference) is the larger one.