it will always have 20 proton (+) and it may have a random amount of electrons that depends if neutrally charged it will be 20 electrons (-) negatively charged -19 electrons and positively charged is +21 electrons
Calcium has twenty electrons in each atom.
Each calcium atom has 20 protons and 20 electrons. This is because the atomic number, which is 20 for calcium, represents the number of protons in the nucleus of its atom, and in a neutral atom, the number of electrons is equal to the number of protons.
20 of each
20 protons and 20 electrons
Calcium carbonate has 16 valence electrons. Calcium contributes 2 valence electrons, while each oxygen atom contributes 6 valence electrons.
Calcium is an element, which means that it is made up protons/electrons and neutrons. Each calcium atom contains a total of 20 protons/electrons, and 20 neutrons.
The formula for calcium iodide is CaI2. This means that the calcium atom has transferred one electron to each of two iodine atoms, for a total of two electrons transferred.
In the compound calcium iodide, one calcium atom transfers 2 electrons to one iodine atom. This results in both atoms achieving a stable electron configuration – calcium with a full outer shell and iodine with a complete octet.
Ca3N2 has a Lewis structure that starts with a Calcium atom in the center. From this Ca atom, there are two single bonds, each connected to a Nitrogen atom. Each nitrogen atom then has a double bond with a single Calcium atom.
Calcium has 20 protons and electrons. The symbol for calcium is Ca and its atomic number is 20.
during the formation of calcium iodide,calcium donates two of its +ve ions each to a fluorine atom(2 in number) thereby making its octet and also fulfills the octet formation of each of fluorine atom..
Two valence electrons are transferred from the calcium atom to the iodine atom in the formation of calcium iodide. This transfer results in the formation of calcium ions (Ca2+) and iodide ions (I-), which then form an ionic bond to create the compound calcium iodide (CaI2).