This question can be answered through the application a little bit of algebra. Allow me to demonstrate:
First, assign variable (essentially letter) values to the amounts of each type of milk. In this case, X represents the quarts of 4% butterfat milk, and Y represents the quarts of 1% butterfat milk.
We know that we need 75 quarts of 1% butterfat milk, so no matter how much of each type we mix, they must add up to 75 quarts. Thus...
X+Y=75
That's our first equation. To solve this, we're going to need one more.
To obtain the objective percentage of butterfat, we must convert all percentages into decimal format. Thus 4%=0.04, 1%=0.01, and 3%=0.03. Now, we know that X has 4% butterfat, thus the butterfat content contributed by X milk is represented by
0.04X
And we know that Y milk has 1% butterfat, thus the butterfat content contributed by Y milk is represented by
0.01Y
To calculate the percentage of butterfat in the entire mixture, one must divide the sum of the concentrations by the total volume of 75 quarts, meaning that the beginning of our our second equation would look like this:
(0.04X+0.01Y)/75
And since we want our objective mixture to have a 3% butterfat concentration, the equation would finish out like this:
(0.04X+0.01Y)/75=0.03
Now we have a system of equations.
X+Y=75
(0.04X+0.01Y)/75=0.03
There are many ways to solve this, but one of the most visually demonstrable methods is the method of substitution. This means getting one equation in terms of one variable. The best way to do this would be to set the first equation equal to Y. Thus
Y=75-X
Now, every time that we see Y appear in the second equation, we replace it with (75-X). Like this
(0.04X+0.01(75-X))/75=0.03
Now we can solve this equation for X. The following equation demonstrates multiplying the answer by the denominator of the fraction and the distribution of the 1%
0.04X+0.75-0.01X=2.25
Now we combine like terms and subtract 0.75 from the answer to get
0.03X=1.5
All that's left is to divide the answer by 0.03 to know what X equals
X=50
This means that we're going to need 50 quarts of 4% butterfat milk.
Now, to solve for the 1% butterfat milk. We can simply take the value we found for X and plug it into the modified version of our first equation to get that
Y=75-50
or
Y=25
This means that we will need 25 quarts of 1% butterfat milk mixed with 50 quarts of 4% butterfat milk to obtain 75 quarts of 3% butterfat milk.
This form of algebraic computation can be used to solve any similar problem.
Let x = the number of quarts of .5% milk, then we have x + 4 quarts of 1% milk.
So that,
.005x +.02(4) = .01 (x + 4)
.005x + .08 = .01x + .04 subtract .005x and .04 from both sides
.005x = .04
x = .04/.005
x = 8 quarts of .5% milk
30 quarts of 2 percent 15 quarts of 5 percent
If 'X' is the number of quarts of 6 percent butterfat milk and 'Y' is the number of quarts of the 1 percent butterfat milk then: x + y = 75 quarts and (6x + 1y)/75 = 4 (because we want 4 percent per quart) then solving for the system of equations leads to: x = 45 quarts (the 6 percent) and y = 30 quarts (the 1 percent)
2 quarts
a cow does not make yogurt it makes milk and it is 8 quarts of milk and that equals 2 hole gallons
1500 gal 1 gallon = 4 quarts 1 quart = 0.25 gallon
That is 1.25 quarts
That is 32 fl oz
10 qts 1 gallon = 4 quarts 1 quart = 0.25 gallon
Four quarts in a gallon.
The answer is 16 quarts.
The answer is 16 quarts.
16