Infinitely many.
Suppose the length of the rectangle is L cm where L >= sqrt(24) = 4.899 cm (approx).
Let the breadth of the rectangle be B = 24/L.
Then area = L*B = L*24/L = 24
Since there are infinitely many choices for L, there are infinitely many rectangles.
For example,
5 * 4.8
6 * 4
8 * 3
50* 0.48
60 * 0.4
600 * 0.04
6000 * 0.004
60000 * 0.0004 etc
The answer is Infinite...The rectangles can have an infinitely small area and therefore, without a minimum value to the area of the rectangles, there will be an uncountable amount (infinite) to be able to fit into that 10 sq.in.
technically the number is infinite
You haven't specified the area of the smaller rectangle
That depends on how big the rectangles are.
3 or 6, depending on whether rectangles rotated through 90 degrees are counted as different. The rectangles are 1x12, 2x6 3x4 and their rotated versions: 4x3, 6x2 and 12x1.
3
24 cm squared = 24 cm * 24 cm = 576 cm2 = 576/10000 m2 or 0.0576 m2
thare is only 1 differint rectangles
The answer is Infinite...The rectangles can have an infinitely small area and therefore, without a minimum value to the area of the rectangles, there will be an uncountable amount (infinite) to be able to fit into that 10 sq.in.
18x1 9x2 6x3
Infinitely many.
9
Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. So, there are 5 rectangles with an area of 36 cm^2 is 5.
123x123=123
13
As many as you want, if they are small enough!
There are an infinite number of rectangles for any given area, while there is only one square for any given area. The number of integer-value rectangles depends on the area and the number of integer factors of a whole-number area. Example: a rectangular area of 6 square inches could be enclosed by rectangles that were 1x6, 2x3, 3x2, and 6x1. Non-integer dimensions would include 1.5x4 and 1.2x5 inches.