0 = 0 is an identity and not an equation. Equations have solutions, identities do not.
It has 2 real solutions because the discriminant is greater than zero.
There are no real solutions because the discriminant of the quadratic equation is less than zero.
Infinite.
None.Whatever number you substitute for 'x', 0x will always be 0,and the equation will always become [ 0 = 4 ].No value of 'x' can make [ 0 = 4 ]. There is no solution.
x = -½
It has infinitely many solutions.
There are four solutions to 9x4 plus 27x3 - 4x2 - 12x equals 0. One of the solutions is x = -3.
It has 2 real solutions because the discriminant is greater than zero.
Two: one is 0, the other is -b/a ax2 + bx + c = 0, but c = 0 ⇒ ax2 + bx + 0 = 0 ⇒ ax2 + bx = 0 ⇒ x(ax + b) = 0 ⇒ x = 0 or (ax + b) = 0 ⇒ x = -b/a
There are no real solutions because the discriminant of the quadratic equation is less than zero.
0 + 17, 1 + 16, 2 + 15, etc.; in fact there are infinitely many solutions.
This has infinitely many solutions, for example: 0 + 1,000,000 1 + 999,999 0.5 + 999,999.5 etc.
If: n squared -n -90 = 0 Then the solutions are: n = 10 or n = -9
6
1
Infinite.
None.Whatever number you substitute for 'x', 0x will always be 0,and the equation will always become [ 0 = 4 ].No value of 'x' can make [ 0 = 4 ]. There is no solution.