A solution to an linear equation
cx + d = f is in the form x = a for some a, we call a the solution (a might not be unique).
Rewrite your sentence:
x = 8, 8 is unique. So how many solution does it have?
Infinitely many: they are the same line!
It has two solutions and they are: x = 3.230396696 and x = -2.063730029
There are two solutions for x: x=11 and x=-7
x = 4y = 1Only one solution:x = 1y = 0.25
2x - y = 8 x + y = 1 These are your two equations. They will have two solutions since you have two variables. The solutions are x=3 and y=-2
Your question does not make sense.
There are infinitely many possible solutions. Some are:x - 7abs(sqrt(x + 13))x^2 - 139
X = 8That equation has exactly one solution.The solution is:x = 8
It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
There are 120 solutions.
It has two equal solutions for x which are x = 2 and x = 2
The equation has infinitely many solutions.
There are a number of possible solutions which will have x=2 and y = 10 as solutions but many of them will also allow other solutions. One possibility, with a unique solution, is (x-2)2 + (y-10)2 = 0
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
The solutions to the quadratic equation are: x = -1 and x = 6
The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.
There is one solution. x = -3
only one. look at the problem. x = 8 x has to equal 8. hope i helped! :)
The solutions are: x = 4, y = 2 and x = -4, y = -2
Two solutions and they are:- x = 0 and y = 3
Only one, and you've already told us what it is.The solution is:X = -31
There are many solutions !... 1 x 384, 2 x 192 and 3 x 128 are just three possibilities.
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
[x + y = 6] has an infinite number of solutions.
zero solutions. If you plot these two lines, you will see that they are parallel and do not intersect.