# How many three digit numbers can be made using numbers 1-9?

9 x 8 x 7 = 504 of them

### There are 60 possibilities that can be made for a three digit number using the numbers 2 4 6 8 and 9 how many of these three digit numbers are smaller than 500?

If this is a homework assignment, please consider trying it yourself first, otherwise the value of the reinforcement to the lesson offered by the homework will be lost on you. There are 60 possibilities that can be made for a three digit number using the numbers 2 4 6 8 and 9. (5 choices for the first digit, 4 choices for the second digit, and 3 choices for the third digit - multiply 5, 4…

### How many numbers can you make from 650271 without repeating a digit?

1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on…

### How many 2-digit or 3-digit numbers can be formed using the digits 134568 and 9 which are diisible by 4?

48. Assuming no digit can be used more than once, the two digit numbers divisible by 4 are: 16, 36, 48, 56, 64, 68, 84, 96 8 of them. For any number to be divisible by 4, only the last two digits need be divisible by 4; so for three digit numbers, each of the two digit numbers above can be preceded by any of the remaining 5 digits and still be divisible by 4…

### How many 3-digit numbers can be made using the digits 4 6 7 9?

If the digits may be repeated, there are four choices for the first digit, four choices for the second, and four choices for the third. Thus there are 4x4x4 = 64 possible three-digit numbers with those digits. If the digits may not be repeated, there are still four choices for the first digit, but then only three remaining choices for the second, and then just two choices for the third. In this case there are…

### How many 4 digit numbers can be formed using the digits 1 3 5 7 9?

Using only the numbers 1,3,5,7,9, and using each number only once, we have 5 options for the first digit, then 4 remaining options for the second, 3 remaining options for the third and 2 remaining options for the fourth. This means there are 5x4x3x2 ways to combine the digits 1,3,5,7,9 into a 4 digit number. 5x4x3x2=120, so there are 120 four digit numbers that can be made.

### How many 4 digit combinations can be made from these 3 numbers 2-6-5?

Assuming you're allowed to repeat numbers, the answer is 81. For each digit, you have three choices: 2, 5, and 6. So there are three one-digit numbers you can make, and each one digit number can be combined with any of three other digits to make a two-digit number, giving 9 (3 times 3) possibilities. Now you can take any of the nine two-digit numbers as the tens and ones places in the four-digit number…

### How many even 3-digit numbers can be formed from digits 1 2 3 5 if each digit can be used only once?

### What is the smallest number that can be made by subtracting 2 five digit numbers using the digits 0123456789?

It is difficult to interpret exactly what you are trying to ask. If you allow your five digit number to have leading zeroes and do not allow negative numbers, then 00000 - 99999 = -99999 is the smallest number. If you do allow negative 5 digit numbers, then (-99999) - 99999 = -199998 is the smallest number.

### What is the one 9 digit delectable number which can be made using the digits 1 to 9?

A delectable number has nine digits, using the numbers 1-9 once in each digit. The first digit of a delectable number must be divisible by one. The first and second digits must be divisible by two, the first through third must be divisible by three, etc. There has only been one delectable number discovered: 381654729.

### How do you figure out how many times 5 digit numbers can be made by using the numbers 12345 without repeating a number twice?

The first digit can be any one of 1, 2, 3, 4 or 5. So you can choose the first digit in 5 ways. Having done that, you have only four unused digits. So you can chosse the second digit in 4 ways. Now then you have only three digits left so the third digit can be chaosen in 3 ways and so on. Total number of ways: 5*4*3*2*1 = 120

### How many three digit numbers can be made with 1 2 and 0 used repeatedly?

You can make 27 unique three-digit numbers using the three digits 0, 1, and 2. i.e. for each of the three digits abc, there are 9 possible orders of those, from aaa to ccc. The 9 starting with 0: 000 001 002 010 011 012 020 021 022 * the combinations are the same as the numbers 0 to 26 expressed in base 3 (000 to 222) 26 base 3 = 222 = 18 +…

### How many 4 digit numbers have only odd numbers?

625. Here's how: There are five odd digits {1,3,5,7,9} so our numbers will be made using only these digits. This is the same number of possibilities as if you had a base 5 number system where the allowed digits are {0,1,2,3,4}. For a 1 digit base-5, there are 5 possibilities, for a two digit base-5 there are 5² = 25 possibilities, so for a 4-digit, there are 5^4 = 625 possible. This is the same…