Well... let's figure it out.
So the answer is, between the number 1 and 100 an 8 appears 20 times.
11 times
As a digit in other numbers it appears 20 times
It appears 25 times.
The digit appears eleven time from 1 to 100.
If you count 11 as 2 instances, the digit 1 appears 18 times if you don't count 10, 19 times if you do. 10,11,12,13,14,15,16,17,18,19,21,31,41,51,61,71,81,91
11 times
146 times.
As a digit in other numbers it appears 20 times
#include<iostream> #include<array> #include<sstream> std::array<int,10> get_frequency (int range_min, int range_max) { if (range_max<range_min) std::swap (range_min, range_max); std::array<int,10> digit {}; for (int count {range_min}; count<=range_max; ++count) { std::stringstream ss {}; ss << count; std::string s {}; ss >> s; for (auto c : s) { ++digit[c-'0']; } } return digit; } int main () { std::array<int,10> digit {}; digit = get_frequency(1, 89); std::cout << "In the range 1 to 89...\n"; for (int d {0}; d<10; ++d) { std::cout << "\tthe digit " << d << " appears " << digit[d] << " times.\n"; } } Output: In the range 1 to 89... the digit 0 appears 8 times. the digit 1 appears 19 times. the digit 2 appears 19 times. the digit 3 appears 19 times. the digit 4 appears 19 times. the digit 5 appears 19 times. the digit 6 appears 19 times. the digit 7 appears 19 times. the digit 8 appears 19 times. the digit 9 appears 9 times.
73
It appears 25 times.
The digit appears eleven time from 1 to 100.
Including the one in ' 1 ' and the one in '100', there are 21 1s.Every other digit 2 - 9 appears 20 times between 1 and 100 .
If you count 11 as 2 instances, the digit 1 appears 18 times if you don't count 10, 19 times if you do. 10,11,12,13,14,15,16,17,18,19,21,31,41,51,61,71,81,91
Many are named only 4 times. In many of the genealogical lists names are mentioned but the people are not dealt with in any detail. If we deal only with those whose names begin with the letter A, we find in the King James version the word - Abia - appears 4 times the word - Abiah - appears 4 times the word - Abinoam - appears 4 times the word - Achsah - appears 4 times the word - Adin - appears 4 times the word - Ahiah - appears 4 times the word - Ahiman - appears 4 times the word - Annas - appears 4 times the word - Arah - appears 4 times the word - Attai - appears 4 times the word - Azgad - appears 4 times the word - Azubah - appears 4 times All of these 'words' are the names of people.
Assuming you are asking how many times the digit 1 appears when writing the numbers 400 to 500: It appears in the tens place once (41x where x is any digit 0-9) so there will be 10 occurrences of it here. It appears in the ones place for every digit in the tens place (4x1) so there will be 10 occurrences of it here. However, the number 411 has been counted twice, once as 41x and again as 4x1. Thus the digit 1 will be written 10 + 10 - 1 = 19 times.
how many times gerater is the underlined digit 5 in 365,486,201 than the digit 5