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What is the program to figure out how many numbers from 0 to 9 are needed for 1 to 89 for example?
Wiki User
∙ 8y ago
#include<iostream>
#include<array>
#include<sstream>
std::array<int,10> get_frequency (int range_min, int range_max) {
if (range_max<range_min)
std::swap (range_min, range_max);
std::array<int,10> digit {};
for (int count {range_min}; count<=range_max; ++count) {
std::stringstream ss {};
ss << count;
std::string s {};
ss >> s;
for (auto c : s) {
++digit[c-'0'];
}
}
return digit;
}
int main () {
std::array<int,10> digit {};
digit = get_frequency(1, 89);
std::cout << "In the range 1 to 89...\n";
for (int d {0}; d<10; ++d) {
std::cout << "\tthe digit " << d << " appears " << digit[d] << " times.\n";
}
}
Output:
In the range 1 to 89...
the digit 0 appears 8 times.
the digit 1 appears 19 times.
the digit 2 appears 19 times.
the digit 3 appears 19 times.
the digit 4 appears 19 times.
the digit 5 appears 19 times.
the digit 6 appears 19 times.
the digit 7 appears 19 times.
the digit 8 appears 19 times.
the digit 9 appears 9 times.
Wiki User
∙ 8y ago
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