once
6
There are 4 cups in a quart. ( so 5 cups doesn't go into it)
Any integer of which both 5 and 7 are factors.
yes
Here's a simple way to solve it: 2*3=6 6*3=18 18*3=54 54*3=162 162*3=486 486*5=2,430 2,430*7=17,010 In simpler terms, 2*3*3*3*3*3*5*7=17,010.
5
1 goes in 45 times. 3 goes in 15 times. 5 goes in 9 times. 9 goes in 5 times. The rest don't go in.
3 times, remainder 5
3 with remainder 5.
3 with remainder 2.
It goes: 360/72 = 5 times
3 times, with the remainder of 3!
5 goes into 13 two times with 3 left over.
three goes into 52 164 times
5 goes in 5 remainder 2 7 goes in 3 remainder 6
5/60ths of one time
Well simply what you do is see how many times 5 goes into 3 and if you think 5+5+5=15 which is 3 groups of 5.