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A series-wound commutator motor has the best starting torque because the torque is proportional to the square of the current, and the starting current is set by a current-limiting resistor which is switched out as the motor builds up speed.
Ac motor has a low starting torque so that DC series motor used in railways cause DC motor has high starting torque
Becoz it use frequecy to start
A screwdriver allows you to exert more torque on a screw. Torque is defined as the product of the force exerted and the distance from the center of rotation. Torque is essentially a rotational force. It is simple to increase torque, simply increase the distance from the center that the force is being applied, and there is greater torque without increasing your effort. The handle is made to be wide, so that a greater torque can be exerted. It is also much easier to grip a screwdriver than it is to grip a screw. That also plays a factor.
With some motor designs, as the motor starts to accelerate, its torque tends to fall somewhat before starting to increase again. The point of lowest torque in this region of the curve is termed the 'pull-up torque'.
yes
The torque which is produced during the starting of motor is simply called as starting torque.
Not exactly,torque is the force that affects rotational motion; the greater the torque, the greater the change in rotational motion. It is always specified with regard to the axis of rotation.
A series-wound commutator motor has the best starting torque because the torque is proportional to the square of the current, and the starting current is set by a current-limiting resistor which is switched out as the motor builds up speed.
when u make a deeper hole then more surface area is in contact with the walls and more chips is in a flutes, so that's why the torque is greater
load is heavier so starting torque is requiredAnswerBecause the same current is passing through both the armature and field windings, the torque is proportional to the squareof the current. Since the starting current is alway high (no back emf), the torque will be very high indeed.
The torque would be the same, as torque measures the rotational force between the two objects, not necessarily the output at either end.
the perpendicular force applied at the end of a wrench handle. Because torque= Fd / T = F d cos θ therefore the greater the distance the greater the torque. T=torque F=force d=distance cos=cosine θ=theta
at starting or initial stage there is no acceleration,it requires more force or power to move any body during initial stage,where as in running condition,it also requires some force or power whioch is less then the imitial power.hence the starting torque is always > pull up torque
If you push on the center there is less distance to the hinge. The greater the distance from the hinge, the greater the torque to open it for the same force ( force x distance = torque)
You create a purely 'rotatory force' or torque when you have two forces of equal magnitude but opposite direction pushing or pulling on an object. The greater the forces the greater the torque, and the greater the perpendicular distances between the two forces the greater the torque. Note that because the forces are equal and opposite, the object will not accelerate in any direction. But because there is a perpendicular distance between the forces the object will start to rotate.
The starting current is about 30 % of the direct-on-line starting device. The starting torque is about 25 % of the direct-on-line starting torque. The stress on an application is reduced compared to the direct-on-line starting method.