That would be 0. The ground state of every element except for Hydrogen is 1s2 which has no unpaired electrons. (only valence electrons have the ability to be unpaired).
Full configuation of Fe would be:
1s2 2s2 2p6 3s2 3p6 4s2 3d6
WWWWWWWWWRRRRRRROOOOOOONNNNNNGGGGGGG!!!!!!!
that would be 5 unpaired electrons
- Rav D.
In the iron atom, there are 4 unpaired electrons.
4
2.
2
An atom of yttrium (Y) has an electron configuration of 1s2,2s2,2p6,3s2,3p6,4s2,3d1, so it has one unpaired electron in the 'd' orbital.
5 electrons where two electrons are paired and three are unpaired
In the element bromine (Br), there is only 1 unpaired electron. It has 7 valence electrons, so 3 pairs, plus an unpaired electron.
A silicon atom has 4 unpaired electrons.
An atom of antimony in its ground state has 3 unpaired electrons.
There are 5 unpaired electrons in Fe^3+ in its ground state.
4
2.
5 unpaired electrons There are 5 unpaired electrons in the Fe3+ ion. The reason for this is that Iron has the electron configuration Ar3d5.
There are 5 unpaired electrons in Fe^3+ in its ground state.
Any in the neutral atom.
There are no unpaired electrons in an unexcited neutral mercury atom; its outer shell contains only two s electrons that are paired, as are all the electrons in the filled inner shells of the atom.
54
There are 0 unpaired electrons which would make it diamagnetic
2