5 electrons where two electrons are paired and three are unpaired
The Lewis structure of fluorine contains 9 electrons, which 7 of them are valence. This means the letter F will be in the middle with 7 dots surrounded it, which would represent the 7 valence electrons.
If phosphorus forms a monatomic ion, it gains electrons and form a phosphide ion. More commonly, however, phosphorus forms a polyatomic anion including one or more oxygen atoms. The bonds within these polyatomic anions are covalent, but phosphorus is considered to have a positive oxidation number in such anions, and positive oxidation number corresponds to losing electrons.
This one can be a little trick because unlike most elements boron is happy with six electrons instead of eight. So boron would be connected to the iodines with three single bonds. I'm not too sure on how to type the lewis structure so it will look right, but i'm sure you can figure it out. Boron is the central atom surrounded by three iodines with single bonds, and remember boron only need six electrons. And this lewis structure has no resonance and makes a polar molecule with a shape of trigonal planar, with an angle of 120 degrees. Hope this helps!
If you mean elemental Phosphorous (As in, just a chunk of P), I believe that the reaction would go to Phosphorous pentachloride like this: P + 5 Cl--> PCl5 THe Lewis Dot structure works out that way, anyways.
If phosphorous occupie the gallium sites, it would be n type semiconductor since it has more number of valence electrons than gallium and if it occupie the sites of the arsenic sites there is no change since the valency of arsenic and phosphorous be the same
more
The Lewis dot structure of elemental (biatomic) oxygen (O) have three of its sides surrounded by valence electrons. The Lewis dot would be 3 of these individual O2 structures: .. .. :O::O: .. ..
the Lewis structure of B or Boron would have three small dots posing as electrons. These dots can be placed anywhere around the B symbol.
The Lewis structure of fluorine contains 9 electrons, which 7 of them are valence. This means the letter F will be in the middle with 7 dots surrounded it, which would represent the 7 valence electrons.
A action is a positively charged ion, so it would have less electrons that a neutral atom. Keep in mind that every electron adds -1 to the overall charge of the ion, so subtracting electrons adds +1 to the charge.
It would have fewer electrons. A cation is a positively charged ion which means that there are fewer negatively charged electrons than positively charged protons.
The Lewis dot for lithium nitride (Li3N) would show 8 electrons (4 pairs) on the N with a -3 charge and no electrons on the 3 Li with each having a +1 charge.
Umm lets see here, the Lewis dot diagram for phosphorus trifluoride would consist of deep depth of concentration dilemma between the two variables using the quadratic formula and postulates. screw you guuyys, im going home
B is in the center, with the three F's around it. Two F's have three lone pairs of electrons and one F has two lone pairs and a double bond with B.
O=O The Lewis dot structure without the lone pairs of electrons.
It is essentially useless to draw Lewis structures for ionic compounds, but if you must, it would look like this:[K^+] S^2- [K^+] and each K has no electrons around it and the S has 8 electrons around it. The S would have 6 dots (its own electrons) and 2 exes (x) which would represent the electrons given by the 2 K atoms.
No, not exactly. It is an ionic compound so it would not have a Lewis dot structure. However, the carbonate anion, CO3^2- does have a Lewis dot structure.