There are 5 unpaired electrons in Fe^3+ in its ground state.
none.
12 are paired, 3 are unpaired To figure this out make a Bohr diagram! :)
Yes, there is. To overly-simplify matters, magnetisation relies on the amount of coherently orientated unpaired electrons that exist in the material. This amount is obviously not infinite (because the material only has so many electrons, unpaired or otherwise) and so will hit a cap for the material in question. There are many types of magnetisation and all sorts of intricacies exist but this is a good way to look at it.
Any atom with unpaired electrons in it's orbital exhibits paramagnetism, that is that it will be attracted into an inducing magnetic field. Phosphorous has 15 electrons: 1s>2e-(all paired) 2s>2e- 2p>6e-(all paired) 3s>2e-(these two are paired) 3p>3e-(note that these are the unpaired electrons that cause it to be paramagnetic) All this is because a moving negative charge produces a magnetic field if there are two electrons in the same orbital they always spin in opposite directions cancelling each other out. When there are unpaired electrons that creates the magnetic field.
There are 3 unpaired electrons.
zero - there are no unpaired electrons
three unpaired electrons
There are no unpaired electrons in strontium.
6 unpaired electrons
A silicon atom has 4 unpaired electrons.
3 unpaired electrons
they're are zero unpaired electrons.
5 unpaired electrons There are 5 unpaired electrons in the Fe3+ ion. The reason for this is that Iron has the electron configuration Ar3d5.
There are 5 unpaired electrons in Fe^3+ in its ground state.
Cesium has 1 unpaired electron.
There are 5 unpaired electrons in Fe^3+ in its ground state.