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repulsive forces between unshared pairs of electrons
Lone electron pairs give the geometry a triangular base, while double bonds make the molecular geometry bent or angular.
Since Selenium is in the same column as Oxygen and Sulfur, you would expect it to bond just like them. As a halogen, chlorine wants to make one bond so your final answer would be. Cl-Se-Cl with two lone pairs (that's 4 electrons) on selenium and 3 lone pairs (that's six electrons) on EACH chlorine.
The shape would tend to be trigonal pyramidal. An example would be ammonia, NH3.
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The nitrogen atom in ammonia has one unshared pair of electrons.
CO2 does not have unshared pairs of electrons.
1 pair
None
There would be three unshared pairs of electrons in a molecule of hydrogen iodide.
repulsive forces between unshared pairs of electrons
Yes it does for a fact
The molecule of chlorine has a covalent bond the the charge being equal distributed.
Lone electron pairs give the geometry a triangular base.
Oxygen has six (6) valence electrons. In the formation of a water molecule, two (2) of the valence electrons forms a covalent bond with two other hydrogen atoms leaving the water molecule with 2 unshared pairs of electron.
there are 10 unshared electrons