18
You mean this form of the electron configuration. [Xe] 4f^14 6s^2 5d^10 6p^3 This is Bismuth and it is in the 5A nitrogen group and it has 5 valance electrons and needs three electrons to complete its valance octet.
XeF4 Xe has 8 valance electrons. F has 7 valance electrons * 4 = 28 valance electrons 8 + 28 = 36 valance electron total. Now, there are 4 bonds between Xe and the 4 F's, so that is a total of 8 electrons shared. 36 - 8 = 28 valance electrons left over. That means that 6 each go around the fluorine atoms as three lone pair per atom and one electron for the exon atom, unless this is a charged molecule.
There are 27 valance electrons.
2 valance electrons
Iodine has 7 valance electrons
They have different numbers of valance electrons
6 valence electrons
6 valence electrons
there are six
Two.
none
2