Chlorine is number 17 in the Periodic Table, so using the electron shell arrangement,
2:8:7:
It has 7 electrons in its valance shell so its charge becomes Cl7+ when these 7 electrons are 'donated' (= lost to, as reductant) to oxygen (only in oxyacid or salt perchlorate).
Other valence values are +5, +3 and +1 in oxyacids: chlorate, chlorite and hypochlorite, respectively.
A chlorine atom has 7 valence electrons, as it is in group 17 of the periodic table. A chloride ion has 8 valence electrons, as it gains an additional electron to achieve a full octet and a stable electron configuration.
I think that because chlorine has 17 electrons in all, and ten of them are filled up on the first two shells, then seven of them should be on the third shell, so seven of them are valance electrons.
The anion of OCl (hypochlorite ion) has 8 valence electrons. This is because oxygen contributes 6 valence electrons and chlorine contributes 7 valence electrons. The overall negative charge of the anion adds one more electron, totaling 8 valence electrons.
ClO2− = 7+6(2)+1=20-------------------------------------------------------------Cl= in group 7A=7O= in group 6A=6---------------------------------------------------------------Add +1 = because we have one (-) negative charge.
Chlorine has seven (7) valence electrons and seventeen (17) electrons total in its ground state (not an ion or isotope).
Chlorine has 7 valence electrons. A chloride ion has 8.
A chlorine atom has 7 valence electrons, as it is in group 17 of the periodic table. A chloride ion has 8 valence electrons, as it gains an additional electron to achieve a full octet and a stable electron configuration.
In the question, it should be either "chlorine atom" or "chloride ion". Chlorine atom has 7 valence electrons. Chloride ion has 8 valence electrons.
The hydrogen ion H+ is without electrons.
Cl- has 8 valence electrons. This is because chlorine, in its neutral state, has 7 valence electrons (group 17), and the -1 charge of the chloride ion indicates the addition of an extra electron.
if you are asking about ICl4- ion then there are 28 valence electrons and 8 binding ones.total of 36 electrons
I think that because chlorine has 17 electrons in all, and ten of them are filled up on the first two shells, then seven of them should be on the third shell, so seven of them are valance electrons.
Cl2 is the diatomic molecule of chlorine (Cl) . It has 14 valence electrons, 7 in each atom. When chlorine forms a chloride ion, an atom accepts an electron and becomes Cl- (negative ion).
The anion of OCl (hypochlorite ion) has 8 valence electrons. This is because oxygen contributes 6 valence electrons and chlorine contributes 7 valence electrons. The overall negative charge of the anion adds one more electron, totaling 8 valence electrons.
A chlorine ion is monatomic ― it is just Cl-.
Chlorine will gain one electron when forming an ion. Chlorine therefore fills its valence electron shell with 8 e-. Chlorine usually bonds with group 1 metals, like Na (Sodium).
ClO2− = 7+6(2)+1=20-------------------------------------------------------------Cl= in group 7A=7O= in group 6A=6---------------------------------------------------------------Add +1 = because we have one (-) negative charge.