It will take 36 volts to make 12 amps go through 3 ohms of resistance. Ohm's law states that the current in amperes is equal to voltage over resistance.
Use Ohm's Law: V = IR (voltage = current times resistance).
You use Ohm's Law to make your calculation. Volts = Amps x Resistance Amps = Volts / Resistance
Ohm's Law: voltage is current times resistance, so 8 amps times 2 ohms is 16 volts.
The voltage needed to make a resistance measurement varies in proportion to the Ohms value being measured. Resistance measurements in the order of thousands and up to one Megohm are low enough to be made with a 1.5 volt or similar cell. However, resistance measurements in the order of hundreds to thousands of Megohm will require a higher voltage of up to 500 Volts DC. A Megger is a device that uses hundreds of volts to make resistance measurements.
tazers start off at 50,000 volts to make contact through the skin and then is switches to 5,000 after it's made it through the skin to keep you stunned
In short, no. There are ways to make the voltage rise, but inverting the power will not help you. If you don't care about the amount of Amps you have, the simplest way to raise the voltage would be to add resistance to the line. Volts and amps are linked by Ohm's law, which states that V=IR, where V is volts, I is current (in amps), and R is resistance in ohms. Therefore you can create a higher voltage at the cost of amperage by adding resistance to your line.
The equation, I=V/R (Current = Voltage/Resistance) determines the current, so if you increase both V and R, you will be able to get the same current (with a bit of adjustment to make it exact)example:10 Volts & 2 Ohms resistance = 5 Amps Current20 Volts & 4 Ohms resistance = 5 Amps Current
A 10 watt bulb is defined by the voltage supply and the resulting current. So to make the math simple, suppose you have a 10 watt incandescent bulb designed to work at 20 volts. That means it will draw 1/2 amps. Watts = Volts x Amps. The resistance of the bulb is then Volts / Amps so in this case the resistance of the bulb would be 40 ohms. So our mythical bulb has a resistance of 40 ohms with 20 volts across the bulb in our example. Now if we put two of these bulbs in series with the same 20 volts we now have a total resistance of 80 ohms supplied by 20 volts and the circuit will draw 1/4 amp. This lower current will cause the bulbs to be dimmer.
Using Ohm's law, we can find the current (I) in a circuit where 3 ohms is the resistance (R) and 12 volts is the appllied voltage (V). [(E) means energy]I = V / R = 12 / 3 = 4 amps.Visit this link http://www.csgnetwork.com/ohmslaw2.html for making Ohm's Law calculations.
First thing voltage does not flow current does. Voltage is the potential or pressure needed to make the current flow. Current is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit. To make the current flow you have to adjust the resistance of the circuit and that would be the water in this case. Salt added to water will make the water conductive so the resistance can be adjusted thereby making the current rise or fall depending on the water solution's resistive properties. The equation that you should consider using is Amps = Volts/Resistance.
To produce 60 watts at 120 volts, you need 0.5 amps (Watts = Volts * Amps) At 120volts, a 240ohm resistor would produce 0.5 amps (Amps = Volts / Resistance) A 60 watt bulb will have a resistance of 240 ohms. Note that this is the resistance while the bulb is hot. You might measure a different resistance if you use an ohm meter because the filament is cold.
Watts are a unit of power and Volts are a unit of electric potential, so they cannot be directly compared. However, Watts and Volts can be related byWatts = Volts * AmperesorWatts = (Volts^2) / Ohmswhere Amperes are a unit of current and Ohms are a unit of resistance. So, for example, if a lightbulb draws .333 Amps of current at 120 Volts, it is a 40 Watt bulb. (.333 A * 120 V = 40 W)