(n-1)! ways
5 people, so 4! ways
I do not believe that answer is correct. Look at it this way:
Let the first person sit anywhere. Then the remaining 4 people can be seated in 4! (4 factorial = 4 * 3 * 2 * 1) Therefore 4! = 24 ways of seating 5 people around a circular table.
There are 4! = 24 ways for 5 people to sit at a round table because we consider the first person's seat as fixed and arrange the rest around him/her.
There are 27 choose 25 ways, which is equivalent to 27! / (25!(27-25)!) = 351 possible different groups of 25 people that can be formed from a total of 27 people.
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In how many ways can five children sit at round table?
yes
in how many ways can a party of 8 people arrange themselves round a table?
The number of circular permutations of n objects is (n-1)! so in this case the answer is 7! =5040 way to sit 8 people around a table.
7!(6*2*5*4*3*2*1)
6
7!
720
5! * 7!
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211690
5 chairs x 5 people = 25 choices