3 students can be chosen from a class of 30 in (30 x 29 x 28) = 24,360 ways.
But each group of the same 3 students will be chosen in six different ways.
The number of different groups of 3 is 24,360/6 = 4,060 .
30
10
boomadoomadonga
17>=(s/2)
X/2=17
6,375,600
if in a class pupil 47 is opposite pupil 16 when the group is seated in a circle how many students are in the PE class?
There are 11880 ways.
It is: 15C7 = 6435 combinations
62
36 x 35/2 ie 630
we can make 1 group
eighteen
14 boys are in the class
40
5
There would be 6 boy students and 18 girl students in the class.